I need help with a complicated page numbering scheme

[Guest]

I need to create document that has several sections and the page numbering is
required to take this form:

1. The first page of each section begins with the number of that section.
So, the first page of section 1 is 1, the first page of section 2 is 2 and so
on.

2. If the section runs to more than a single page, then the page number of
the second page of that section needs to have appended to it a letter. So,
the second page of section 2 would be numbered 2a, the third page would be 2b
and so on.

I cannot figure out how to do this. Can someone please help me? Thanks.

Rich Newman

 

[Shauna Kelly]

Hi Rich

You will need one field to get the section number, and two nested fields to
get the "a", "b", "c" etc.

To get the section number, use { SECTION }
To get the page number use { = { PAGE } -1 \*alphabetic }

Note that you can't type the {} braces by hand. You must use ctrl-F9 and
type between the braces that Word inserts for you. Once you've typed the
field, use F9 to update it, or ctrl-a F9 to update all fields in the
document. Shift-F9 toggles between the display of a field code and its
results. Alt-F9 toggles the display of field codes and field results for the
whole document.

For more information on page numbering, see
How to control the page numbering in a Word document
http://www.mvps.org/word/FAQs/Numbering/PageNumbering.htm

Hope this helps.

Shauna Kelly. Microsoft MVP.
http://www.shaunakelly.com/word

 

[Guest]

Shauna,

Thank you for this. I have just one more question, if it's not too much
trouble. Can you show me exactly how I need to put the fields on the page to
get the result I need. I've tried a couple of different ways and it doesn't
seem to work. I keep getting the section number, which does not necessarily
correspond to the first page of the section, followd the letter. For example,
the beginning of section 2 is page 5, but I cannot figure out how to use the
fields you showed me to get section 2 to start at page 5 and then have 5a, 5b
and so on. I guess this is something I did not make clear in my original post.

Again, my thanks.

Rich Newman