G
Guest
I have set up a small office as a workgroup. All computers have XP Pro. They
need to have access to shares on one of the computers. I have disabled Simple
Files sharing on that computer and added the shares. Provided I am logged on
as the administrator on any of the other computers, I can access those shares
fine. But when I log in as a user (all with limited accounts) then they
cannot access those shares.
Actually, as I recall when accessing those shares I believe it asks for a
name and password. If I provide the admin name and password, then maybe I can
access them. But that's not what I want to do. I tried creating a single user
on the sharing computer that everyone would use to access those shares, but
that didn't work . I also created individual accounts with the same login
name and password the users use to login to their computers. No success.
(BTW, in all cases I added the users to the share permissions and to the
directory permissions).
Surely there is a way to accomplish this task without using the
administrator login.
Thanks for any input.
need to have access to shares on one of the computers. I have disabled Simple
Files sharing on that computer and added the shares. Provided I am logged on
as the administrator on any of the other computers, I can access those shares
fine. But when I log in as a user (all with limited accounts) then they
cannot access those shares.
Actually, as I recall when accessing those shares I believe it asks for a
name and password. If I provide the admin name and password, then maybe I can
access them. But that's not what I want to do. I tried creating a single user
on the sharing computer that everyone would use to access those shares, but
that didn't work . I also created individual accounts with the same login
name and password the users use to login to their computers. No success.
(BTW, in all cases I added the users to the share permissions and to the
directory permissions).
Surely there is a way to accomplish this task without using the
administrator login.
Thanks for any input.