length from angle of hypotenuse

[Anderson]

If I have the length of the base of a right triangle and the angle of
the hypotenuse how can I derive the length of the hypotenuse and the
height of triangle(side A)?Thanks for any trig refresher one can give
me.

 

[Peo Sjoblom]

Maybe something like this in excel,

COS(angle*PI()/180)=b/c

b is known that gives c=b/COS(angle*PI()/180)

after that use Pythagoras Theorem

a^2+b^2=c^2

we know c and b gives


a^2=c^2-b^2

using excel
a is

=SQRT(c^2-b^2)


now if you use a calculator

cos(angle)=b/c




--
Regards,

Peo Sjoblom

(No private emails please, for everyone's
benefit keep the discussion in the newsgroup/forum)

 

[Paul Valente]

Anderson

Try this
hypotenuse = SUM(H28/COS(RADIANS(M24)))
The height of triangle uses
side A = SUM(TAN(RADIANS(M24))*H28)
where H28 is length of the base
and M24 the given hypotenuse angle at the base

Paul