Inverse Sine Calculation

[Guest]

*
32 * * .5
* X *
***********

I have a triangle with a Hypotenuse of 32 and height of .5. I am trying to
determine what angle X is. On a calculator I take .5/32 = .015625
The inverse sine on a calculator gives the angle of X at .895282987.
How do I replicate this in C# code?

Thanks in advance - Dan

 

[Oliver Sturm]

*
32 * * .5
* X *
***********

I have a triangle with a Hypotenuse of 32 and height of .5. I am trying to
determine what angle X is. On a calculator I take .5/32 = .015625
The inverse sine on a calculator gives the angle of X at .895282987.
How do I replicate this in C# code?

My maths is a bit rusty But I'm sure it should work like this:

double radians = Math.ASin(0.5/32);
double degrees = radiansASine * 180 / Math.PI;

The reason is that the .NET Math functions calculate in radians, so you
have to convert the values. Most calculators have "Deg" and "Rad" modes,
so they do this automatically.


Oliver Sturm

 

[Jon Skeet [C# MVP]]

*
32 * * .5
* X *
***********

I have a triangle with a Hypotenuse of 32 and height of .5. I am trying to
determine what angle X is. On a calculator I take .5/32 = .015625
The inverse sine on a calculator gives the angle of X at .895282987.
How do I replicate this in C# code?

See Math.Asin.