identify specific word in a range of words

[jan]

i'm struggling to find a word in a specif text string, any ideas?

thanks

 

[Ron Rosenfeld]

i'm struggling to find a word in a specif text string, any ideas?

thanks

Did you try the FIND or SEARCH worksheet functions?
--ron

 

[jan]

Ron,

yes I tried to apply the standard functions but cannot solve it myself.

i need to find the string "non approved" in a sentence.

regards.

 

[Otto Moehrbach]

Specifically, what happened when you used Edit - Find? Exactly what did you
do when you used Edit - Find? Otto

 

[Gord Dibben]

You are posting in programming group.

Do you want to use VBA to find the string?

And what will you do with the result when you have found the string?

Do you want to replace with another? Highlight the cell? Highlight the
string within the sentence?

Without programming..............................

Edit>Find>What: not approved

Make sure you don't have "match entire cell contents" enabled.


Gord Dibben MS Excel MVP

 

[Mike H]

Jan,

You aren't being really clear about what you want. The finds the position of
the first letter of the string in the sentence in a1

=SEARCH("non approved",A1)

Having found that what do you want to do?

Mike

 

[jan]

=(IF(D2="30000104";0;IF(ISERROR(FIND("TRAVEL";F2;1));0;IF(ISERROR(FIND("NON
APPROVED";F2;1));0;H2/520))))

F2 contains the text, if it either contains "travel" or "non approved" the
output should be 0 if not the result must be H2/520

 

[jan]

your right.

=(IF(D2="30000104";0;IF(ISERROR(FIND("TRAVEL";F2;1));0;IF(ISERROR(FIND("NON
APPROVED";F2;1));0;H2/520))))

F2 contains the text, if it either contains "travel" or "non approved" the
output should be 0 if not the result must be H2/520

hope this helps

 

[Rick Rothstein]

Here is another way for you to try...

=IF(D2="30000104",0,IF(COUNTIF(F2,"*travel*")+COUNTIF(F2,"*non
approved*")>0,0,H2/520))

 

[jan]

i got it to work, the if tru/ not true where mixed up

=(IF(D4="30000104";0;IF(ISERROR(FIND("TRAVEL";F4));IF(ISERROR(FIND("NON
APPROVED";F4));H4/520;0);0)))

 

[Mike H]

Jan,

Note i've changed ; to , for my machine, change it back for yours

=IF(D2=30000104,0,IF(AND(ISERROR(SEARCH("Travel",F2)),ISERROR(SEARCH("Non
Approved",F2))),H2/520,0))

Mike

 

[Mike H]

Forgot to mention I also took 30000104 out of quotes because I guess its a
number if its really text then put the quotes back

Mike

 

[jan]

thanks guy's, apprecite the help.

regards from the Netherlands