sumproduct to add total amounts for the month

[Annette]

I used the formula for adding number of entries, but now I need to change it
to add the amounts that were collected during each month:

=SUMPRODUCT(--(MONTH(Base!$A$2:$A$1368)=9), --ISNUMBER(Lisan!$D$2:$D$1368))

A B C D
(date) (Status) (Due) (Paid)

9/2/04 30.00 40.00
9/3/04 25.00 25.00
10/1/04 15.00 12.00


Total for column D for September $65.00

How can I change the formula to add the amounts paid per month?

Thanks!

Annette

 

[Bob Phillips]

=SUMPRODUCT(--(MONTH(Base!$A$2:$A$1368)=9), --ISNUMBER(Lisan!$D$2:$D$1368),B
ase!$D$2:$D$1368)

--

HTH

RP
(remove nothere from the email address if mailing direct)

I used the formula for adding number of entries, but now I need to change it
to add the amounts that were collected during each month:

=SUMPRODUCT(--(MONTH(Base!$A$2:$A$1368)=9), --ISNUMBER(Lisan!$D$2:$D$1368))

 

[Johannes]

How about:
=SUMPRODUCT( MONTH(Base!$A$2:$A$1368) = 9 , Lisan!$D$2:$D$1368 )
?

I used the formula for adding number of entries, but now I need to change it
to add the amounts that were collected during each month:

=SUMPRODUCT(--(MONTH(Base!$A$2:$A$1368)=9), --ISNUMBER(Lisan!$D$2:$D$1368))

 

[Annette]

Thanks, Bob ... perfect solution!

=SUMPRODUCT(--(MONTH(Base!$A$2:$A$1368)=9), --ISNUMBER(Lisan!$D$2:$D$1368),B

ase!$D$2:$D$1368)

--

HTH

RP
(remove nothere from the email address if mailing direct)


change

=SUMPRODUCT(--(MONTH(Base!$A$2:$A$1368)=9), --ISNUMBER(Lisan!$D$2:$D$1368))

 

[Frank Kabel]

Hi Johannes

this as well needs the double minus ))
=SUMPRODUCT(--(MONTH(Base!$A$2:$A$1368) = 9) , Lisan!$D$2:$D$1368)

--
Regards
Frank Kabel
Frankfurt, Germany

How about:
=SUMPRODUCT( MONTH(Base!$A$2:$A$1368) = 9 , Lisan!$D$2:$D$1368 )
?


change

=SUMPRODUCT(--(MONTH(Base!$A$2:$A$1368)=9), --ISNUMBER(Lisan!$D$2:$D$13
68))

 

[Johannes]

Yep, guessed that one... only is with sumproduct rigth?

 

[Frank Kabel]

Hi
the double minus is used as ONE possible mathematical calculation to
coerce a boolean value. Instead of this you could use
0+(...)
1*(...)
(..)^1
N(...)
where (...) is a boolean expression

Performance difference is not really an issue though my testing showed
that -- is about 5 - 30% faster than the other ones
(N(...) the second fastest and (...)^1 the slowest one). so don't use
that option

You could also use this to convert numeric values stored as Text to
real numbers (a substitute for the VALUE function)