Shortcut to Access 97 on machine with 97 and 2003

I

Inquirer

Douglas Steele mentioned in a January 10 post to explicitly identify the
correct version of Access to launch when more than one version (specifically
97 and 2003) are installed on the same machine and mdb files from each
version need to be used and preserved in their native format. I have done
this is the past, but have forgotten exactly how. Could somone refresh my
memory on exactly what to put into the shortcut to direct it to the correct
version for the specific file in question?

Thank you,

Darrell
 
D

Douglas J. Steele

The shortcut needs to explicitly point to whichever version of msaccess.exe
is appropriate.

"C:\Program Files\Microsoft Office\Access 97\msaccess.exe" "C:\Some
Folder\SomeFile_97.mdb"

"C:\Program Files\Microsoft Office\Access 2003\msaccess.exe" "C:\Some
Folder\SomeFile_2003.mdb"

(or whatever)
 
D

Darrell

Thank you so much Doug. That is EXACTLY what I needed-the exact syntax of the
command. And, it looks like the 2 adjacent strings with a space between is
the trick.

Thanks,

Darrell
 

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