G
Guest
I had my computer set up to give me a choice to boot either in Win98 (C partition) or WinXP (D partition). I had to reformat & reinstall 98 on C: and it deleted the file (boot.ini?) which gave me the dual-boot option. Last night a friend did something with the boot.ini file (or created a boot.ini file) in either D: or C: and restored the dual-boot option at startup, but now the 98 bootup does not work. The boot.ini reads as follows
[boot loader
timeout=2
default=multi(0)disk(0)rdisk(0)partition(2)\WINDOW
[operating systems
multi(0)disk(0)rdisk(0)partition(2)\WINDOWS="win xp d"
multi(0)disk(0)rdisk(0)partition(1)\WINDOWS="win98 try
We thought that the last line might be written wrong and need some different commands to boot 98 correctly. Please advise. Also, even when I make changed to this boot loader, even when I removed it from the c: root directory, the changes do not affect bootup. It could be that the above is not the actual boot loader but a copy. Please tell me where to find (and how to write) the boot loader that determines what comes on the screen at startup.
[boot loader
timeout=2
default=multi(0)disk(0)rdisk(0)partition(2)\WINDOW
[operating systems
multi(0)disk(0)rdisk(0)partition(2)\WINDOWS="win xp d"
multi(0)disk(0)rdisk(0)partition(1)\WINDOWS="win98 try
We thought that the last line might be written wrong and need some different commands to boot 98 correctly. Please advise. Also, even when I make changed to this boot loader, even when I removed it from the c: root directory, the changes do not affect bootup. It could be that the above is not the actual boot loader but a copy. Please tell me where to find (and how to write) the boot loader that determines what comes on the screen at startup.