logon to a specific ad controller

[Toni Ghatta]

I have a dmz and wan. In my dmz I have an isa srver in a
site the same as 2 adc's. I do not want my isa server
authenticating with an adc from another site. I have setup
ad sites and services but am not sure this will stop cross
wan ad authentication.

Is there a registry key to state which adc by name or ip
address to use. Netbios is disabled on the isa server.

Thanks

Toni

 

[ptwilliams]

If you have DCs and GCs at both sites, and have correctly configured Sites
and Services, the DCs wont go across the WAN unless they can't access the
local ones.

You can (almost) force clients to use a specific DC by modifying the
weighting of DCs, but generally this isn't recommended. If you desire that
a machine at siteA only logs on at siteA ensure sites and services are fine
and that DNS is functioning and you'll be fine.


--

Paul Williams
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I have a dmz and wan. In my dmz I have an isa srver in a
site the same as 2 adc's. I do not want my isa server
authenticating with an adc from another site. I have setup
ad sites and services but am not sure this will stop cross
wan ad authentication.

Is there a registry key to state which adc by name or ip
address to use. Netbios is disabled on the isa server.

Thanks

Toni

 

[Toni Ghatta]

I thought so. Thanks

 

[Robert Greene [MSFT]]

Configure Sites Site Links, and then Subnets in Sites and Services and Link
them to the proper sites.

269098 HOW TO: Configure Windows 2000 Subnets
http://support.microsoft.com/?id=269098

247811 How Domain Controllers Are Located in Windows
http://support.microsoft.com/?id=247811

314861 How Domain Controllers Are Located in Windows XP
http://support.microsoft.com/?id=314861

316812 HOW TO: Create and Configure a Site Link in Active Directory in
Windows
http://support.microsoft.com/?id=316812

321253 HOW TO: Configure Site Link Replication in Windows 2000
http://support.microsoft.com/?id=321253

318480 HOW TO: Create and Configure an Active Directory Site in Windows 2000
http://support.microsoft.com/?id=318480



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