J
JCO
I have a friend's laptop at my house. I'm cleaning off the spyware. Hoping
to
speed the thing up. The laptop is an HP Pavilion ZE4500 that has an Athlon
XP2500 in it. I know desktop's running the Athlon 2500 run at
approximately 2.00 GHz. I'm not sure what the laptop is suppose to run (if
it is different).
First Question:
Dose anybody know the speed of a laptop running the Athlon XP2500?
When I do a Properties on "My Computer" the computer fluctuates from 519Mhz
to 1.86Mhz. I'm trying to figure out what would change this processor
speed. Why wouldn't stay at 1.86 (assuming that 1.86 is the max). The
battery is fully charged and I'm running with the laptop plugged into the
wall. If it is part of an Energy Conservation, logic tells me that it
should not drop in power when it is plugged in.
Is there a better way to determine the processor speed?
Other Question:
Can someone clear this up?
Can it be a power problem (battery or power converter)?
Can it be Energy Conservation (although it is plugged in and the battery is
fully charged).
Thanks (sorry about having so many questions)
to
speed the thing up. The laptop is an HP Pavilion ZE4500 that has an Athlon
XP2500 in it. I know desktop's running the Athlon 2500 run at
approximately 2.00 GHz. I'm not sure what the laptop is suppose to run (if
it is different).
First Question:
Dose anybody know the speed of a laptop running the Athlon XP2500?
When I do a Properties on "My Computer" the computer fluctuates from 519Mhz
to 1.86Mhz. I'm trying to figure out what would change this processor
speed. Why wouldn't stay at 1.86 (assuming that 1.86 is the max). The
battery is fully charged and I'm running with the laptop plugged into the
wall. If it is part of an Energy Conservation, logic tells me that it
should not drop in power when it is plugged in.
Is there a better way to determine the processor speed?
Other Question:
Can someone clear this up?
Can it be a power problem (battery or power converter)?
Can it be Energy Conservation (although it is plugged in and the battery is
fully charged).
Thanks (sorry about having so many questions)