M
Mark
Hi
My PC is in an office with two Internet connections.
LAN connection (Gateway 192.168.0.254 (My IP Address 192.168.0.7))
and
802.11 Connection (Gateway 192.168.1.254 (My IP Address 192.168.1.43))
Both of these connections work individually, but I want to be able to
combine these two connections so that I can utilise the bandwidth of
them both.
To do this, I am attempting to bridge the two connections (???)
However, when I select the two connections in NETWORK CONNECTIONS and
select BRIDGE CONNECTIONS, I get the error message
"To create a Network Bridge, You must select at least two LAN or High
Speed Internet connections that are not being used by Internet
Connection Sharing"
Neither of these connections are being used in this way....
I have disabled the Windows Firewall/Internet Connection Sharing (ICS)
service, but I continue to get this message...
This machine may in the past have used the service. Can't remember...
It's XP Pro SP2 by the way...
Any ideas? (will what I am doing actually work anyway, this problem aside?)
TIA
Mark
My PC is in an office with two Internet connections.
LAN connection (Gateway 192.168.0.254 (My IP Address 192.168.0.7))
and
802.11 Connection (Gateway 192.168.1.254 (My IP Address 192.168.1.43))
Both of these connections work individually, but I want to be able to
combine these two connections so that I can utilise the bandwidth of
them both.
To do this, I am attempting to bridge the two connections (???)
However, when I select the two connections in NETWORK CONNECTIONS and
select BRIDGE CONNECTIONS, I get the error message
"To create a Network Bridge, You must select at least two LAN or High
Speed Internet connections that are not being used by Internet
Connection Sharing"
Neither of these connections are being used in this way....
I have disabled the Windows Firewall/Internet Connection Sharing (ICS)
service, but I continue to get this message...
This machine may in the past have used the service. Can't remember...
It's XP Pro SP2 by the way...
Any ideas? (will what I am doing actually work anyway, this problem aside?)
TIA
Mark