Help with formula

S

SS

Original formula from previous post...
=(("12:00"-MAX(C11,--"7:00"))*0.3+(MAX("23:00",C11)-MAX(C11,"12:00"))*0.4+(C12-MIN(C12,"23:00"))*0.5)*24




I have changed the formula to


=(("12:00"-MAX(C11,--"7:00"))*0.3+(MAX("23:00",C11)-MAX(C11,"12:00"))*0.4+(C12-MIN(C12,"23:00"))*0.5)*C13




As a test I have put in aircon running for 1 hour between 10-11 am

So this should return a value of .30 It is however returning a value of
2.17 Can anyone help with this. Thanks




Original post.....
I am trying to work out the cost of running an aircon unit.
The electricity costs are different during the 24 hour day.

In cell C7 I have costs per KW from 06.59- 12.00am (lets say .30 p an
hour)
In cell C8 I have costs from 12.01-22.59pm (lets say
.40p per hour)
In cell C9 I have costs for 23.00 - 06.58am (lets say
.50p per hour)

In cell C11 I have time aircon switched on
In cell C12 I have time aircon switched off

In cell C13 I have total hours switched on
 
P

Pete_UK

In front of each of those times shown in quotes you need to put the
double minus to convert them to proper values, so try this:

=((--"12:00"-MAX(C11,--"7:00"))*C7+(MAX(--"23:00",C11)-
MAX(C11,--"12:00"))*C8+(­C12-MIN(C12,--"23:00"))*C9)*24

Times are stored as fractions of a 24-hour day, which is why you need
the 24 at the end.

Hope this helps.

Pete
 

Ask a Question

Want to reply to this thread or ask your own question?

You'll need to choose a username for the site, which only take a couple of moments. After that, you can post your question and our members will help you out.

Ask a Question

Top