Extract filename from url

[Scott Reynolds]

Hello!

Could someone please provide me a sample, how to extract filename from url?

http://www.mydomain.com/eng/Default.aspx -> Default.aspx

Thanks

Scott

 

[Joyjit Mukherjee]

Hi,

use the Scheme property of the Uri object. It will give you the scheme
(file, news etc.) for the Uri object.

Regards
Joyjit

 

[Guest]

You can use System.Url class to get each parts of url. but u can not get the
filename alone.

Uri u = new
Uri("http://www.mydomain.com/eng/Default.aspx");
u.LocalPath

string s = "http://www.mydomain.com/eng/Default.aspx";
string fileName= s.Substring(s.LastIndexOf("/") +
1));
You one of substring method to find out the filename alone.

Regards,
Govind.

 

[Greg]

string s = "http://www.mydomain.com/eng/Default.aspx";

string fileName = s.SubString(s.LastIndex(@'/')+1);

hope this helps

 

[Davide Vernole [MVP]]

Hello!

Could someone please provide me a sample, how to extract filename
from url?

http://www.mydomain.com/eng/Default.aspx -> Default.aspx

Thanks

Scott

You can do it in different ways. A easy way could be this:

Uri uri = Request.Url;

string[] segment = uri.Segments;

int position = segment.Length - 1;

string page = segment[position];

Response.Write(page);

 

[Scott Reynolds]

Thank you all!

 

[Raghavendra T V]

Hi Scott,

You can get the pagename using this code.
string strPageName = System.IO.Path.GetFileName(Request.Path);

or

string strPageName =
System.IO.Path.GetFileName("http://www.mydomain.com/eng/Default.aspx");

Thanks

Raghavendra

 

[mortb]

try:

string URL = "http://www.mydomain.com/eng/Default.aspx";
int afterLastSlashIndex = URL.lastIndexOf('/') + 1;
string filename = URL.substring(afterLastSlashIndex , ULR.length -
afterLastSlashIndex);

/mortb

 

[Devdex Developer]

Mystr="http://www.mydomain.com/eng/Default.aspx"
Dim filename As String()
filename = mystr.Split("\")
response.write(filename(filename.Length - 1))
Hope this would help

 

[TJS]

Dim Mystr As String ="http://www.mydomain.com/eng/Default.aspx"
Dim filename As String()
filename = mystr.Split("/")
response.write( filename (uBound(filename)) )