Count help

C

Curtis

I need to count the number of customers listed in a certain column. They can
appear multiple times but I just want to count each different customer once

thanks
 
D

Domenic

Curtis said:
I need to count the number of customers listed in a certain column. They can
appear multiple times but I just want to count each different customer once

thanks


For a unique count, try the following formula that needs to be confirmed
with CONTROL+SHIFT+ENTER...

=SUM(IF(FREQUENCY(IF(A2:A100<>"",MATCH("~"&A2:A100,A2:A100&"",0)),ROW(A2:
A100)-ROW(A2)+1),1))

Adjust the ranges, accordingly.
 
A

Ashish Mathur

Hi,

You may try this formula

=sumproduct((1/countif(range.range))

This assumes that there are no blank cells in the range.

--
Regards,

Ashish Mathur
Microsoft Excel MVP
www.ashishmathur.com
 
R

ryguy7272

There are so many ways to do this:
< -- =SUMPRODUCT((A2:A105<>"")/(COUNTIF(A2:A105,A2:A105&"")))
< -- =SUMPRODUCT((A2:A998<>"")/(COUNTIF(A2:A998,A2:A998)+(A2:A998="")))
< --
=SUM(IF(FREQUENCY(IF(LEN(A2:A999)>0,MATCH(A2:A999,A2:A999,0),""),IF(LEN(A2:A999)>0,MATCH(A2:A999,A2:A999,0),""))>0,1))
Note: This is a CSE Function
< -- =SUMPRODUCT((A2:A105<>"")/COUNTIF(A2:A105,A2:A105&"")*(A2:A105<>""))
< -- =SUMPRODUCT(--(A2:A999<>""),1/COUNTIF(A2:A999,A2:A999&""))
< --
=SUM(--(FREQUENCY(IF(A2:A2705<>"",MATCH(A2:A2705,A2:A2705,0)),ROW(INDIRECT("1:"&ROWS(A2:A2705))))>0))
Note: This is a CSE Function
< -- =COUNT(1/FREQUENCY(A1:A400,A1:A400))
< -- =SUM(1/COUNTIF(C13:C17,C13:C17))
Note: This is a CSE Function & it fails if there are any blanks in between
< -- =SUM(IF(A2:A400<>"",1/COUNTIF(A2:A400,A2:A400)))
< --
=SUM(IF(FREQUENCY(IF(A2:A1001<>"",MATCH("~"&A2:A1001,A2:A1001&"",0)),ROW(A2:A1001)-ROW(A2)+1),1))

HTH,
Ryan--
 

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