conditional formula needed

[kylefoley2000]

it might be possible to do this as a conditional formula (=if) otherwise a
macro might be needed.

the thing i'm unsure about is this formula looks at the cells beneath it and
keeps looking until a result is returned, i'm not sure if that can be done as
a conditional formula.

if you really want to know what this is for send me a pm and i'll tell you.


if m3 = 0 then ""
if l3 = i then ""
if m3 = 1 and if l3 = "c" and if i3 > 0

and if e4 – d3 < -.0066 then result = 1
write result in n3
else go to row 5

if e5 – d3 < -.0066 then result = 1

if d5 >= d3 then result = 0

i seriously doubt this will happen but in case it does
if e5 – d3 < -.0066 and if d5 > d3 then result = "ambiguous"
else go to next row
keep going down the rows (it should not take any more than 3 or 4) until
either


if i3 < 0
and if e4 – d3 > .0066 then result = 1
write result in n3
else go to row 5

if e5 – d3 > .0066 then result = 1
if d5 < d3 then result = 0

must loop through all the rows, there 8800 of them

 

[kylefoley2000]

any thoughts on this?

 

[Duke Carey]

It's hard for anybody to have an idea because your statement of the problem
is long on minute points but short on a concise statement of what you are
trying to do. Help us help you by being clear and concise about what you are
trying to accomplish.