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#### Paul Black

This is Lotto Based.

There is a System in Lotto called "Wheels".

A Lotto Wheeling System is a Special Pattern to Arrange Numbers into

Combinations. This System can be Used Over and Over again with Different

Numbers. A Lotto Wheel is Constructed in such a way that if the Winning

Numbers Fall in the Group of Numbers you have Selected, you will Always

have a Winning Combination Somewhere. If for Example, you have a Group

of 12 Numbers then the Lotto Wheel you Select should have the Numbers

1-12 Arranged in Sets of Numbers ( Each Set is 6 Numbers ). You then

take the Wheel and Substitute your Numbers in the Wheels Pattern and

Simply Replace all the 1's in the Pattern with your First Number, all

the 2's with your Second Number, all the 3's with your Third Number,

etc. All Wheels give a Guarantee. For Example, the Wheel 24,6,3,6,50

Means, there are 24 Different Numbers Used in the Wheel, there are 6

Numbers Drawn, the Guarantee of having 3 Numbers in at Least 1

Combination if ALL the 6 Numbers Drawn are in the Selected 24 Numbers.

I have a Set of 6 Number Combinations in Cells "G13:L27" ( the Number of

Combinations could be More or Less ).

In this Example I am Using a Wheel with 24 Numbers :-

1,3,7,12,15,16

1,4,5,17,20,21

1,8,9,10,19,22

1,13,14,18,23,24

2,3,6,9,21,23

2,10,12,14,16,20

2,11,15,19,20,24

3,4,7,10,18,24

3,5,7,14,17,19

4,6,8,14,15,22

4,9,11,13,16,19

5,10,13,15,17,23

5,11,12,18,21,22

6,8,12,16,17,24

7,8,13,20,22,23

Here is the Code that someone has Kindly Provided which Cycles through

ALL Combinations and Compares ALL the Combinations with ALL the

Combinations in the Above Wheel. The Below Code Finds the Coverage (

Total Combinations ) of 5 Numbers if 5 Numbers are Matched …

Code:

Sub test_5()

Dim a, dic As Object

Set dic = CreateObject("Scripting.Dictionary")

a = Range("g13").CurrentRegion.Value

For i = 1 To UBound(a, 1)

For ii = 1 To 2

For iii = ii + 1 To 3

For iv = iii + 1 To 4

For v = iv + 1 To 5

For vi = v + 1 To 6

z = a(i, ii) & "," & a(i, iii) & a(i, iv) & a(i,

v) & a(i, vi)

If Not dic.exists(z) Then

dic.Add z, Nothing

n = n + 1

End If

Next vi, v, iv, iii, ii, i

Set dic = Nothing

Range("O16") = n

End Sub

… and Produces the Correct Result of 90.

How can the Code be Modified to Also Produce the Combinations Covered

for the Categories …

Matched = Covered Combinations

2 if 5 = 42,504

3 if 5 = 35,720

4 if 5 = 4,140

5 if 5 = 90 ( the Code Already Provides this Result )

… Please.

I was Told for the Interpretation of the 3 if 5 Category that you Need

to Cycle through ALL 5 Number Combinations that can be Constructed from

the Total Numbers Used in the Wheel ( 24 in this Case ). So if the Wheel

Contains "x" Unique Numbers, you Need to Cycle through ALL 5 Number

Combinations from those "x" Numbers. Then you Need to Scan the Wheel for

Each 5 Number Combination Produced and Compare it with Each Line in the

Wheel to see if that Line Matches the 5 Number Combination in *EXACTLY*

3 Numbers. If it does, then that Combination of 3 if 5 is Covered and

Added to the Total and there is NO Need to Continue to Check for that

Particular Combination Any Further. You then go onto the Next

Combination to Check and so on Until ALL Combinations have been Cycled

through and Checked with the Wheel.

I Hope I have Explained this Clear Enough.

Many Thanks in Advance.

All the Best.

Paul