Calculate formulas with feet & inches

  • Thread starter Thread starter Guest
  • Start date Start date
G

Guest

How do you add or subtract feet & inches in formulas IE 12' 4" + 12' 8"...
 
If you convert your data to inches you can use:
ROUNDDOWN(A1/12,0)&" feet "&A1-12*ROUNDDOWN(A1/12,0)&"
inches"

Try putting inches (your result) in A1 for this example.
 
So theres no way to format data for particular cells as feet,inches persay?
IE cell A1 is 12"4" and cell B1 is 12' 8" and formula for cell c1 would be
Sum(a1,b2).

GerryK said:
If you convert your data to inches you can use:
ROUNDDOWN(A1/12,0)&" feet "&A1-12*ROUNDDOWN(A1/12,0)&"
inches"

Try putting inches (your result) in A1 for this example.
 
Thanks for the website, good info, gets me close the formula i need, now i
just need to deal with the fractional part if i have 1/2"...
 
This formula converts to inches & does square feet. You can adapt for your
need.
Feet Inches Feet Inches Sq Ft Price Square
Feet

15 9 18 8 $ 3.87 294.000

=(C6+IF(D6<>" ",D6/12,0))*(E6+IF(F6<>" ",F6/12,0))
 
I've refrased my question in another post just now. Im trying to find
diferances in elevation for surveying a floor. What I'd like to do is --- In
cell A1 12' 4" &1/2". in cell A2 put 12'3"&3/4 then find the differance(but
with many more "before & after" measurements).
 
I'm trying to calculate window and door measurements into square feet. Any
suggestions?
Peggy
 
How do you enter the height and width?

If you use one cell each, then for 5' 6", make sure you enter:
5.5
in the cell (5 and 1/2 feet)
or even
5 6/12

Then you can just multiply the two cells:

=a1*b1
(say).

If you do your entry in inches:

66
for 5.5 feet

then
=a1*b1/144



If you use two cells for each dimension (feet and inches)

A1 = height in feet
b1 = left over inches

=(a1+b1/12)*(c1+d1/12)
 

Ask a Question

Want to reply to this thread or ask your own question?

You'll need to choose a username for the site, which only take a couple of moments. After that, you can post your question and our members will help you out.

Ask a Question

Back
Top