c# - listBox onScroll event

  • Thread starter Thread starter John Keers
  • Start date Start date
J

John Keers

Can anyone tell me how to fire and use a listBox onScroll event. The
language I am using is C# in a windows forms application

thanks
 
Hi John,


ListBox doesnot provide a interface for your to manipulate the scrollbar
directly. As a workaround, you can try sending WM_VSCROLL message via
PInvoke. For
example:


Class Win32
{
[DllImport("User32.Dll")]
public static extern bool SendMessage(IntPtr hWnd,int Msg,int
wParam,int lParam);
public const int WM_VSCROLL = 0x0115;
public const int SB_LINEDOWN = 1;



}


Win32.SendMessage(listBox1.Handle,Win32.WM_VSCROLL,Win32.SB_LINEDOWN,0);

Hope this helps.


Regards,

Luke
 
Herfried K. Wagner [MVP];6999999 said:
"John Keers" <[email protected]> schrieb:
> Can anyone tell me how to fire and use a listBox onScroll event. The
> language I am using is C# in a windows forms application

<URL:http://groups.google.de/groups?q=WM_VSCROLL+csharp+listbox>
Click to expand...

Googling "listbox onscroll", this thread is the third hit in the list. Your post linking to google is about as helpful as tits on a bull. Let's assume everyone was a giant douchenozzle like yourself, and in reply to every question simply posted a link to google... we'd have a results list of google search links. Congratulations on contributing to useless recursion. :cheers:

[MSFT];7004033 said:
Hi John,


ListBox doesnot provide a interface for your to manipulate the scrollbar
directly. As a workaround, you can try sending WM_VSCROLL message via
PInvoke. For
example:


Class Win32
{
[DllImport("User32.Dll")]
public static extern bool SendMessage(IntPtr hWnd,int Msg,int
wParam,int lParam);
public const int WM_VSCROLL = 0x0115;
public const int SB_LINEDOWN = 1;



}


Win32.SendMessage(listBox1.Handle,Win32.WM_VSCROLL,Win32.SB_LINEDOWN,0);

Hope this helps.


Regards,

Luke
Click to expand...

Thanks, Luke. This is the sort of information which someone who DOES search for a particular topic expects to find.
 
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