Roundup or Ceiling Function to round to a specific number

[Guest]

Does anyone know how to use the Round Function or the Ceiling function to
round up to a specific number? Example: I have the number 1288 in D8 and I
have a formula in E8 which says “=D8/0.67â€, the result is 1922. But I would
like “1922†to round up to “1925â€. Had it been “1927â€, I would want it to
round up to 1929. Can anyone tell me how to do this?

 

[Bob Phillips]

=CEILING(A10,5)-(AND(MOD(A10,10)<>0,MOD(CEILING(A10,5),10)=0))

--
HTH

Bob Phillips

(replace somewhere in email address with gmail if mailing direct)

 

[Don Guillett]

try
=ROUNDUP(A1/5,0)*5

 

[bplumhoff]

Hello,

=CEILING(A1-1,4)+1

HTH,
Bernd

 

[Guest]

Bob,

I tried it and it worked, but to be honest with you I really don't
understand what or how it is working can you explain for me. This formula is
a bit advanced for me and I would really like to understand it so I can use
it on a large spreadsheet. Also is there anyway to combine the formula you
gave me with the one simple one that I had initially "=D8/0.67". Bob you
are great!!

 

[bplumhoff]

Hello,

Is this really what you wanted:

Input Bob's Mine
1913 1915 1913
1914 1915 1917
1915 1915 1917
1916 1919 1917
1917 1919 1917
1918 1919 1921
1919 1919 1921
1920 1920 1921
1921 1925 1921
1922 1925 1925
1923 1925 1925
1924 1925 1925
1925 1925 1925
1926 1929 1929
1927 1929 1929
1928 1929 1929
1929 1929 1929
1930 1930 1933
1931 1935 1933
1932 1935 1933
1933 1935 1933
1934 1935 1937
1935 1935 1937

(Just want to make sure

Regards,
Bernd

 

[Guest]

Hi,

I am really looking for what Bob gave me. I need things to round up to
either a 5 or a 9. Thanks,

 

[Bob Phillips]

I'll give it a shot at explaining it.

if 1627 were to round up to 1630, it would have been easy, just

=CEILING(A1,5)

I used this as the basis of the solution, but then tested as to when the
result of that was exactly divisible by 10 (MOD(CEILING(A1,5),10)=0). Thus
any number thatn rounds up to a multiple of 10 passes this test, so by just
subtracting it -(MOD(CEILING(A1,5),10)=0), which takes one away. SO anything
that is a multiple of 10 when rounded up to the nearest 5 gets 1 taken
away,. I included the test for the number being divisible by 10 without
rounding up to the nearest 5 (MOD(A1,10)<>0) so that numbers that started as
multiples of 10, 1630 etc., didn't get changed to 1629. So 1628 round to
1629, as does 1629, but 1630 stays at 1630, 1631 rounds to 1635. The AND is
just to combine both tests and return a single TRUE/FALSE result which the -
will negate (-1 or -0).

As for the second bit, I think you just need to change all instances of A10
in my formula to D8/0.67.

--
HTH

Bob Phillips

(replace somewhere in email address with gmail if mailing direct)

 

[Guest]

Bob,

I did as you suggested, changed the A10 to D8/0.67. It worked now I will
test it out on larger spread sheet. Thanks so much for your explanation. It
makes sense I just have to absorb it all. Thanks much.

 

[Guest]

Hi Bob,

Need your help one more time. I tried it out on a few numbers and it worked
but I need to tweek it. A number which ends with a "5" like "1555" rounds
up to 1559, I need it to stay the same, because I need numbers to end with 5
or 9, therefore no change would be required for 1555. Also, I noticed that
the numbers that ended with a "0" like "1630" actually rounded up to 1635.
How would I alter the formula so that anything ending with a "0" would round
down to "29" instead of up to "35"?

 

[Bob Phillips]

I don't get the same results as you are getting. 1625 is staying at 1625 and
1630 is staying at 1630, neither is rounding up.

I think it is the D8/0.67, I think that has a small increment in it which
makes a number that looks like 1625 actually be something like 16.000001 ort
so, which will go up.

Try this (getting ugly) version

=CEILING(ROUND(D8/0.67,0),5)-(MOD(CEILING(ROUND(D8/0.67,0),5),10)=0)

--
HTH

Bob Phillips

(replace somewhere in email address with gmail if mailing direct)

 

[joeu2004]

I think it is the D8/0.67, I think that has a small increment in it which
makes a number that looks like 1625 actually be something like 16.000001 ort
so, which will go up.

I am not following this discussion closely, but I wonder if D8*2/3
yields the desired results. Just a WAG, really.

 

[joeu2004]

Errata ....

I am not following this discussion closely, but I wonder if D8*2/3
yields the desired results. Just a WAG, really.

First, that should be D8*3/2. Second, ignore my comment. It does not
seem relevant to the crux of the thread.

 

[Bob Phillips]

That thought occurred to me Joe, but I decided against messing with the OPs
data/original req <G>

--
HTH

Bob Phillips

(replace somewhere in email address with gmail if mailing direct)

 

[bplumhoff]

Hi Bob,

I suggest to take
=IF(AND(A1-TRUNC(A1,-1)>5,A1-TRUNC(A1,-1)<=9),CEILING(A1+1,5)-1,CEILING(A1+5,10)-5)

Instead of A1 we can take D8*3/2 again.

Regards,
Bernd

 

[Guest]

Hi Bob,

I think I will be using your ugly version. It works very well. Its the
better of the two. It rounds down a number like 1990 to 1989 and rounds up
where it needs to. Thanks so much for your help.

 

[Bob Phillips]

It was Ugly Angie, but necessary. Those numbers were bigger than 1930 etc.

--
HTH

Bob Phillips

(replace somewhere in email address with gmail if mailing direct)

 

[joeu2004]

Hi Bob,
I think I will be using your ugly version. It works very well.

Ugly or not, I think it fits the needed solution well. It took me a
long time to understand the poorly-stated and every-changing problem
specification. When I finally did, I independently came up with
exactly the same solution. Kudos to Bob for seeing through the
confusion early on.

It appears that your rounding rules are: round up to a multiple of 5,
but when that results in a multiple of 10, round down from there (i.e.
subtract one) so that the number ends in 9 instead of 0. That is
exactly how Bob's expression reads. So frankly, I see nothing ugly
about solution. "The punishment fits the crime" ;-).

 

[Rachael F]

Hello

I need a similar formula to Angie.

In Cell L92, I would like to combine L92*1.03
with a trunc formula that rounds to 49p if L92*1.03< or = 49p
or that rounds to 99p if L92*1.03 is 50p-99p

eg. £12.06 would round to £12.49
£12.49 would stay as £12.49
£12.58 would round to £12.99
£12.99 would stay as £12.99

I am using 2007.

Many thanks & best wishes.

Rachael

 

[T. Valko]

Try this:

=CEILING(L92*1.03+0.01,0.5)-0.01