How do I use inverse trigonometry in access?

[Guest]

Can anybody give me any advise on how I would write an expression using
Inverse Trigonometry in an query in Access.
I can use normal trig as: Tan(2/7) / Cos(0.54) / Sin(12/9)
But when I want to write an expession to find an angle of a right-angled
triangle, I can not work out how to use the inverse function of trig.
Normally the expression would be something like: (2/7)Tan-1 [or to the
power of minus 1] / (12/9)sin-1 / 0.54Cos-1.
But I can not understand how to write an expession using the inverse function,
any help would be gratefullly appreciated.

 

[Douglas J. Steele]

Go into the VB Editor and search Help for Derived Math Functions. The
formulae for each of the equations you want are shown there.

 

[Dan Artuso]

Hi,
somelinks of interest:
http://mathworld.wolfram.com/InverseCosine.html
http://tutorial.math.lamar.edu/AllBrowsers/AlgebraTrigReview/InverseTrig.asp

Maybe these will help, I've long ago forgotten most of my math.

 

[DonCao]

Use this formula in query (microsoft access):

Inverse_Tan:Atn([1st angle])*180/3.141592654

 

[Van T. Dinh]

Why would you perform an inverse Tan of an angle?

The input of Inverse Tan should be a real number (a ratio without unit), not
an angle ...