Where to insert "application.startuppath" code?

[kimiraikkonen]

Hello experts,
I want my external application run from the root folder where my
project (.exe) resides. For example, my main project (.exe) should be
in the same directory with my external file works with parameter "-b".
But i couldn't know where to insert application.startuppath. That code
block works OK but "doit.exe" only runs from "c:\". I want it to run
in any directory as enough to be in the same directory with my
compiled exe project. Here is my code:

Dim psInfo As New System.Diagnostics.ProcessStartInfo("c:\doit.exe", "-
b")
psInfo.WindowStyle =
System.Diagnostics.ProcessWindowStyle.Normal
Dim myProcess As Process =
System.Diagnostics.Process.Start(psInfo)
myProcess.WaitForExit()
MsgBox("Completed", MsgBoxStyle.Information, "Completed")


How can i configure or put application.startup line?

Thank you.

 

[Cor Ligthert[MVP]]

Kimi,

I assume you mean this one?

http://msdn2.microsoft.com/en-us/library/system.windows.forms.application.startuppath.aspx

Cor

 

[kimiraikkonen]

Kimi,

I assume you mean this one?

http://msdn2.microsoft.com/en-us/library/system.windows.forms.applica...

Cor

Hello Cor,
Thanks for your response. Good article but i couldn't know where to
put, i get some errors when debugging about "overload failed because
no acceptable "new"...bla bla".

How can i re-organize my code and make my external process run from
root folder where my main project resides?

Thanks.

 

[kimiraikkonen]

Hi again

Ok i've fixed by typing:

psinfo.workingdirectory = application.startuppath before
process start line.

Now it's OK. Very thanks.