# Updating a value using a matrix

N

#### Nancy Lytle

I have to create some values based on a formula that is fairly straight
forward, but I seem to be having a bit of a mental block on pieces of it.
This is my first time trying anything like this and any help or pointers
will be much appreciated.
Overall I am trying to create a function either behind a form or in a module
where the user can pick the item then input the values of x, y and come up
with z .

TIA,
Nancy

The formula is like this:
item: vehicle
Type 1 includes offRoadvehicles (pickup, SUV, by brand and make)
Type 2 includes all others (by brand and make)
y is one rating for an item, say mechanical condition
x is a rating for an item on a different condition, like body condition
z is a percentage that some one came up with based on y and x as to how much
above or below a set value they are willing to go to purchase the item (for
example might be willing to pay 10% over asking for a OffRoad in excellent
mechanical condition but with a less than perfect body and 5% less for a non
OffRoad that in excellent mechanical condition but needs body work.

If Left(IbrandandmakeID, 3) in (a list of about 25 pieces of 3 character
text) then

If y = 5 then
if x = 5 then
z = 120
Elseif x = 4 then
z= 50
'x goes down to 3, then 2, then 1 with the z also changing by no set
formula - just taking numbers off a 'spreadsheet
End if

ElseIf y= 4 then
if x = 5 then
z = 100
Elseif x = 4 then
z= 40 'x goes down to 3, then 2, then 1 with the z also changing
by no set formula - just taking numbers off a 'spreadsheet
End if

' y goes down to 3 then 2 then one, again with a lookup to x's value (1-5)
and based on those 2 numbers z is gotten from the spreadsheet.

Then there is the overall Else statement for IDNumbers not in the IN clause.
The the asking price for the item will be multiplied by the z percentage to
get the price we are willing to pay up to.

I am have one problem and one question:
Problem:
I cannot seem to get the
If Left(IDNumber, 3) in (123,156,195) then
part to work.

My question is:
Is there an easier way to do this that I am not seeing?

M

#### Marshall Barton

Nancy said:
I have to create some values based on a formula that is fairly straight
forward, but I seem to be having a bit of a mental block on pieces of it.
This is my first time trying anything like this and any help or pointers
will be much appreciated.
Overall I am trying to create a function either behind a form or in a module
where the user can pick the item then input the values of x, y and come up
with z .

The formula is like this:
item: vehicle
Type 1 includes offRoadvehicles (pickup, SUV, by brand and make)
Type 2 includes all others (by brand and make)
y is one rating for an item, say mechanical condition
x is a rating for an item on a different condition, like body condition
z is a percentage that some one came up with based on y and x as to how much
above or below a set value they are willing to go to purchase the item (for
example might be willing to pay 10% over asking for a OffRoad in excellent
mechanical condition but with a less than perfect body and 5% less for a non
OffRoad that in excellent mechanical condition but needs body work.

If Left(IbrandandmakeID, 3) in (a list of about 25 pieces of 3 character
text) then

If y = 5 then
if x = 5 then
z = 120
Elseif x = 4 then
z= 50
'x goes down to 3, then 2, then 1 with the z also changing by no set
formula - just taking numbers off a 'spreadsheet
End if

ElseIf y= 4 then
if x = 5 then
z = 100
Elseif x = 4 then
z= 40 'x goes down to 3, then 2, then 1 with the z also changing
by no set formula - just taking numbers off a 'spreadsheet
End if

' y goes down to 3 then 2 then one, again with a lookup to x's value (1-5)
and based on those 2 numbers z is gotten from the spreadsheet.

Then there is the overall Else statement for IDNumbers not in the IN clause.
The the asking price for the item will be multiplied by the z percentage to
get the price we are willing to pay up to.

I am have one problem and one question:
Problem:
I cannot seem to get the
If Left(IDNumber, 3) in (123,156,195) then
part to work.

My question is:
Is there an easier way to do this that I am not seeing?

The problem with your If statement is that IN is not a VBA
operator. (It would work if you used it in a query's Where
clause or a text box expression.)

In VBA, you have to use a bunch of ORs to accomplish the

If Left(IDNumber, 3) = 123 OR Left(IDNumber, 3) = 156 OR
Left(IDNumber, 3) = 195 Then

BUT, you should seriously consider using a table for this
kind of thing instead of hard coding those value in a VBA
procedure. If you did this, then there would be several
ways of retreiving the value of z from an appropriately
designed table.

N

#### Nancy Lytle

I must really be having a bad brain day!
So I would create a table and place in it those values that I want to check
against (the special values) and then in the code, have it match the input
against each row in the table using a query to see if there is a match, and
if there is, flag it one way and take the code through the "special process"
and if not, no flag and it goes through regular processing.
So easy, and yet I didn't think of it. I guess I was looking for something
harder.
And then just create a matrix table or two? This is the somewhat harder
part, bcause there is no consistency in how z is derived, there is no
"mechanical counts for 60% of the decision and Body for 40%" the z part of
the formula is just someone best guesstimate based on 20 years of knowledge.
Maybe that's the sticking point.
Any additional ideas would be welcomed.

Thanks again,
Nancy

M

#### Marshall Barton

I'm not 100% sure I understand the details of your operation
here, but I 'm pretty sure I would go a couple of steps
further. I'm thinking of using at least two tables like
this:

Table name: BrandMakeCategory
Fields: Code Text(3) <Prinmary Key>
Cat Integer <Brand and Make Category>
Example Records:
XYZ 1
XXX 1
ABC 2
PQY 3
PQZ 3
etc.

Table name: ZScore
Fields: VType Integer <Vehicle Type>
Y Integer
X Integer
BMC Integer <Brand and Make Category>
Z Integer
With a unique index (Primary Key) composed of VType, X and Y
Example records:
1 5 5 1 120
1 5 4 1 50
1 4 5 1 100
1 4 4 1 40
etc.

With all that in place, you can retrieve a Z value by using
a query like:

SELECT Z
FROM ZScore As ZS INNER JOIN BrandMakeCategory AS BMCat
ON ZS.BMC = BMCat.Cat
WHERE BMCat.Code = Left(Forms!yourform.IbrandandmakeID, 3)
And ZS.Y=Forms!yourform.txtY And ZS.X=Forms!yourform.txtX

The next step after that would be to create a form/subform
for the express purpose of allowing some person to easily
enter/edit the values in these tables.

N

#### Nancy Lytle

Thanks, I think that last bit has really gotten me over the hump and headed
in the right direction. I am trying to set up something a little less
cumbersome than the current process which involves multiple batch queries
Again, many thanks,
Nancy
Marshall Barton said:
I'm not 100% sure I understand the details of your operation
here, but I 'm pretty sure I would go a couple of steps
further. I'm thinking of using at least two tables like
this:

Table name: BrandMakeCategory
Fields: Code Text(3) <Prinmary Key>
Cat Integer <Brand and Make Category>
Example Records:
XYZ 1
XXX 1
ABC 2
PQY 3
PQZ 3
etc.

Table name: ZScore
Fields: VType Integer <Vehicle Type>
Y Integer
X Integer
BMC Integer <Brand and Make Category>
Z Integer
With a unique index (Primary Key) composed of VType, X and Y
Example records:
1 5 5 1 120
1 5 4 1 50
1 4 5 1 100
1 4 4 1 40
etc.

With all that in place, you can retrieve a Z value by using
a query like:

SELECT Z
FROM ZScore As ZS INNER JOIN BrandMakeCategory AS BMCat
ON ZS.BMC = BMCat.Cat
WHERE BMCat.Code = Left(Forms!yourform.IbrandandmakeID, 3)
And ZS.Y=Forms!yourform.txtY And ZS.X=Forms!yourform.txtX

The next step after that would be to create a form/subform
for the express purpose of allowing some person to easily
enter/edit the values in these tables.
--
Marsh
MVP [MS Access]

Nancy said:
I must really be having a bad brain day!
So I would create a table and place in it those values that I want to
check
against (the special values) and then in the code, have it match the input
against each row in the table using a query to see if there is a match,
and
if there is, flag it one way and take the code through the "special
process"
and if not, no flag and it goes through regular processing.
So easy, and yet I didn't think of it. I guess I was looking for
something
harder.
And then just create a matrix table or two? This is the somewhat harder
part, bcause there is no consistency in how z is derived, there is no
"mechanical counts for 60% of the decision and Body for 40%" the z part
of
the formula is just someone best guesstimate based on 20 years of
knowledge.
Maybe that's the sticking point.

J

#### John Spencer (MVP)

Marshall,

I agree with your proposed solution to this particular problem. HOWEVER, I
think there is a solution to the IN problem that is a bit less cumbersome to
code then using all those OR statements. Especially handy if you need to modify

Quote
In VBA, you have to use a bunch of ORs to accomplish the

If Left(IDNumber, 3) = 123 OR Left(IDNumber, 3) = 156 OR
Left(IDNumber, 3) = 195 Then
End Quote

SELECT CASE Left(IDNumber,3)
Case "123", "156", "195"
'Since Left returns a string value make sure you
'check for string values

'Do whatever you need to do

END SELECT

That said, I still think a table-driven solution (as you proposed) is a better solution.

M

#### Marshall Barton

John said:
Marshall,

I agree with your proposed solution to this particular problem. HOWEVER, I
think there is a solution to the IN problem that is a bit less cumbersome to
code then using all those OR statements. Especially handy if you need to modify

Quote
In VBA, you have to use a bunch of ORs to accomplish the

If Left(IDNumber, 3) = 123 OR Left(IDNumber, 3) = 156 OR
Left(IDNumber, 3) = 195 Then
End Quote

SELECT CASE Left(IDNumber,3)
Case "123", "156", "195"
'Since Left returns a string value make sure you
'check for string values

'Do whatever you need to do

END SELECT

That said, I still think a table-driven solution (as you proposed) is a better solution.

RIght, much better than an If with a long string of ORs.

Another way is to get the Expression Service to evaluate the
IN operator:

If Eval(Left(IDNumber, 3) & "IN (123, 156, 195)") Then

But, it's still has hard coded data values.

G

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Now delete the first name in the list and move the other names one number up
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STEP nº 3
Change what you consider necessary of this article, and post it on at least
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GOOD LUCK!!!