Type Mismatch in Auto-Open Macro

[Guest]

I am getting Runtime Error "13" (Type Mismatch) on the following code:
Sub WorkBook_Open()
Sheets("Install").Select
ActiveSheet.Protect password = True
Sheets("Summary").Select
End Sub
When I remove the line "ActiveSheet.Protect password = True" it clears the
message but I really need this to be done. This is happening in Office 2002
but not in Office 2000. I can run the command at any time other than opening
and it does not give the error message. Why does it just do this in the
Auto-Open macro and what can be done to fix it?
Thanks.

 

[Tom Ogilvy]

Your missing a colon:

Sub WorkBook_Open()
Sheets("Install").Select
ActiveSheet.Protect password:=True
Sheets("Summary").Select
End Sub

 

[Robin Hammond]

Carl,

The password part is meant to be a string, not a boolean value and you need
a colon in there. e.g.

ActiveSheet.Protect Password:="My Password"

I'd guess this is working on 2000 because you don't have the Option Explicit
setting on. Since the first parameter expected is the password, what you are
doing is setting a password string of "False" which is the evaluation of the
"password = True" statement.

Robin Hammond
www.enhanceddatasystems.com

 

[Guest]

Thanks, Tom. You have been a tremendous help!

Your missing a colon:

Sub WorkBook_Open()
Sheets("Install").Select
ActiveSheet.Protect password:=True
Sheets("Summary").Select
End Sub