Type Mismatch (13)


A

Alan

The code below is giving me a runtime error 13 (type mismatch), but
I cannot figure out why. It is failing on this line:

sPDFName = Replace(sWordName, pos, 4, ".pdf")

but it appears to use the right syntax. This was tested with an input
of WordDocPath = "test.doc"

Alan

Sub ProcessWord (WordDocPath As String)

Dim sPDFName As String, sPDFPath As String
Dim pos As Integer, sWordName As String

sWordName = WordDocPath
pos = InStr(1, sWordName, ".doc")
If (pos = 0) Then
DisplayErrorMessage (sWordName & " is not a Word document")
Exit Sub
Else
sPDFName = Replace(sWordName, pos, 4, ".pdf")
End If
 
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J

Jacob Skaria

Dear Alan

sPDFName = Replace(sWordName, pos, 4, ".pdf")

In the above code 'pos' should be a string variable. The syntax for Replace
is (expression, find, replace[, start[, count[, compare]]]) where expression
and find are string variables. In your code pos is a integer which returns a
type mismatch error.


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J

Jacob Skaria

Dear Alan

sPDFName = Replace(sWordName, pos, 4, ".pdf")

In the above code variable 'pos' should be a string. The syntax for Replace
is
Replace(expression, find, replace[, start[, count[, compare]]]) where
'expression' and 'find' are string functions. Replace 'pos' with the
substring being searched for.

Eg: Replace("abcd","b","c") = "accd"

If this post helps click Yes
 

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