Can you explain the Abs formula?
It works fine, but how does it??
Thank you
J@@ (Tahiti)
Harlan has given you the mathematics of the formula... let's see if a verbal
description helps any. First off, if you are not familiar with the ABS
function, it simply returns the positive value of its argument, So, ABS(5)=5
and ABS(-5)=5. Now, consider the range given = 153 to 381. The midpoint of
that range is 267 which can be found by adding one half the length of the
range to the lower range value.
Midpoint = 153 + (381 - 153) / 2 = 153 + 114 = 267
As it happens, the short cut for this calculation is to add the endpoints of
the range together and divide by 2
Midpoint = (153 + 381) / 2 = 534 / 2 = 267
which is what Harlan used. Then math behind that is quite simple. Starting
with my original method of calculating the midpoint (and using A and B for
the endpoints of the range)...
Midpoint = A + (B - A) / 2 = A + B/2 - A/2 = A/2 + B/2 = (A + B) / 2
Anyway, the main point to see in this is that all values in the range must
lie within half the length of the range from the midpoint. If you don't see
that at first, think about it... it is sort of a definition. So, if a value
V is to be in the range, then it must be closer to the midpoint than an end
point is. Said another way, the positive difference between V and the
midpoint must be less than half the length of the range. For the given
range, the positive difference of V and the Midpoint is found by ABS(V-267)
and it must be less than half the length of the range which is
(381-153)/2... note that is the second math expression in my original
Midpoint calculation above... which is 114 after completing the math. Okay,
now put it together.. for the value V to be in the range, this expression
must hold...
ABS(V - 267) < 114
For the spreadsheet... A1 is the value V. One final note. If we use just the
"less than" symbol (<), the endpoints are not part of the range. If we use
the "less than or equal" symbol (<=), then the endpoints are part of the
range.
In looking back at what I wrote, I don't think it came out as clear as how I
see it in my head; but perhaps you will find it useful nonetheless.
Rick