Return a column value from a horizontal search

[Spag]

Hello

I'm trying to look across a row for a non blank cell and return what is in
the first cell of the column in which the non blank cell is found. Does
anybody have any ideas how that could be done?

Thanks

 

[Jacob Skaria]

The below formula returns the first value in Col A

=INDEX(A:A,MATCH("*",A:A,0))

If this post helps click Yes

 

[Jacob Skaria]

The below formula returns the first value in Col A

=INDEX(A:A,MATCH("*",A:A,0))

If this post helps click Yes

 

[Jacob Skaria]

First value of row 1 within A1:Z1

=INDEX(A1:Z1,0,MATCH("*",A1:Z1,0))

If this post helps click Yes

 

[Jacob Skaria]

First value of row 1 within A1:Z1

=INDEX(A1:Z1,0,MATCH("*",A1:Z1,0))

If this post helps click Yes

 

[Spag]

Thank you for that however this returns the cell A1 entry even if the cell is
blank. I need it to check which cell in the row is not empty and return the
relevant column entry in row 1

 

[Spag]

Thank you for that however this returns the cell A1 entry even if the cell is
blank. I need it to check which cell in the row is not empty and return the
relevant column entry in row 1

 

[Jacob Skaria]

I misunderstood your query as 1st column instead of 1st Row. The below will
return the first non-blank entry in row1

=INDEX(1:1,0,MATCH("*",1:1,0))


If this post helps click Yes

 

[Jacob Skaria]

I misunderstood your query as 1st column instead of 1st Row. The below will
return the first non-blank entry in row1

=INDEX(1:1,0,MATCH("*",1:1,0))


If this post helps click Yes

 

[Spag]

Thanks but again it doesn't seem to be working, it seems to return the colum
header for the first cell whether blank or not. Please find below an example
of what I'm trying to achieve with column 'a' being the formula column and
row '1' the value to return:

a b c d e
1 one two three four
2 four 1
3 three 1
4
5
6 Four 1

 

[Spag]

Thanks but again it doesn't seem to be working, it seems to return the colum
header for the first cell whether blank or not. Please find below an example
of what I'm trying to achieve with column 'a' being the formula column and
row '1' the value to return:

a b c d e
1 one two three four
2 four 1
3 three 1
4
5
6 Four 1

 

[Jacob Skaria]

With the below data...

In A2 enter the below formula and copy that down. This will look for an
entry 1.

=INDEX($A$1:$Z$1,0,MATCH(1,$B2:$Z2,0)+1)

If you are entering a text value then instead of one then use the below in A2

=INDEX($A$1:$Z$1,0,MATCH("*",$B2:$Z2,0)+1)

 

[Jacob Skaria]

With the below data...

In A2 enter the below formula and copy that down. This will look for an
entry 1.

=INDEX($A$1:$Z$1,0,MATCH(1,$B2:$Z2,0)+1)

If you are entering a text value then instead of one then use the below in A2

=INDEX($A$1:$Z$1,0,MATCH("*",$B2:$Z2,0)+1)

 

[Ashish Mathur]

Hi,

You can try this array formula (Ctrl+Shift+Enter)

=INDEX(E6:E10,MATCH(TRUE,E6:E10<>"",0),1)

--
Regards,

Ashish Mathur
Microsoft Excel MVP
www.ashishmathur.com

 

[Ashish Mathur]

Hi,

You can try this array formula (Ctrl+Shift+Enter)

=INDEX(E6:E10,MATCH(TRUE,E6:E10<>"",0),1)

--
Regards,

Ashish Mathur
Microsoft Excel MVP
www.ashishmathur.com

 

[Spag]

Thank you very much that works perfectly.

With the below data...

In A2 enter the below formula and copy that down. This will look for an
entry 1.

=INDEX($A$1:$Z$1,0,MATCH(1,$B2:$Z2,0)+1)

If you are entering a text value then instead of one then use the below in A2

=INDEX($A$1:$Z$1,0,MATCH("*",$B2:$Z2,0)+1)

 

[Spag]

Thank you very much that works perfectly.

With the below data...

In A2 enter the below formula and copy that down. This will look for an
entry 1.

=INDEX($A$1:$Z$1,0,MATCH(1,$B2:$Z2,0)+1)

If you are entering a text value then instead of one then use the below in A2

=INDEX($A$1:$Z$1,0,MATCH("*",$B2:$Z2,0)+1)