# Retrieve unique items with 2 criteria (USING SUMPRODUCT)

P

#### Paulo

This question was posted before but the solution proposed used different
functions. I would like to insist. Is there a modification to the formula
below, using SUMPRODUCT, that allows to retrieve the number of unique itens
that meet a 2nd criteria?

Original formula:
=SUMPRODUCT((A1:A20<>"")/COUNTIF(A1:A20,A1:A20&""))

In my case, I need the numbers of unique branches (column B) that meet a
specifc criteria in another column (M). So, I have the formula:

=SUMPRODUCT((all!\$B\$2:\$B\$5514<>"")/COUNTIF(all!\$B\$2:\$B\$5514,all!\$B\$2:\$B\$5514&""))

but I need to include the 2nd criteria:

(all!\$M\$2:\$M\$5514=\$A22)

Paulo

Are there any empty cells within the range all!B2:B5514?

No, but then the first part of the function (all!\$B\$2:\$B\$5514<>"") would have
taken care of that.

Let's assume there are no empty cells, if this helps.

Thanks,

Paulo

Try this array formula** :

=SUM(IF(FREQUENCY(IF(All!M2:M5514=A22,MATCH(All!B2:B5514,All!B2:B5514,0)),ROW(All!B2:B5514)-ROW(All!B2)+1),1))

** array formulas need to be entered using the key combination of
CTRL,SHIFT,ENTER (not just ENTER). Hold down both the CTRL key and the SHIFT
key then hit ENTER.

Thanks, but I am already aware of this formula. There was a previous post
where this solution was proposed. What I really wanted was a way of getting
the same result using SUMPRODUCT, but I am afraid it might not be possible.

Regards,

Paulo

the same result using SUMPRODUCT,
but I am afraid it might not be possible.

I'm sure it's *possible* but the formula I suggested is the *most efficient*
at counting uniques if using only the built-in functions. A SUMPRODUCT
version would not be very efficient on 5000+ rows of data.

If you want the most efficient *method* possible then you'd need to go with
a VBA UDF (user defined function). The most efficient UDF that I know of is
included in a free add-in called Morefunc.xll.