Regular Expressions question

[Guest]

Hi all,

let say that my string is :
/// <author> aaa
/// <author> bbb
/// <author> ccc

1. how do i match all the authors except author aaa ?

2. how do i append the string "2006" to the authors names found in #1 ?

Thanks.

 

[Markus Stoeger]

Hi all,

let say that my string is :
/// <author> aaa
/// <author> bbb
/// <author> ccc

1. how do i match all the authors except author aaa ?

2. how do i append the string "2006" to the authors names found in #1 ?

Use the Replace method on the above regex and replace with: ${line} 2006

... there are probably smarter expressions than this..!

hth,
Max

 

[Markus Stoeger]

Use the Replace method on the above regex and replace with: ${line} 2006

.... a bit easier:

///\s<author>\s(?!aaa)(?<author>.*)

and replace with:

$& 2006

Max

 

[Ken Arway]

let say that my string is :
/// <author> aaa
/// <author> bbb
/// <author> ccc

1. how do i match all the authors except author aaa ?

Regex regex = new Regex(@"(?:///\s<author>\s)([^aaa].+)",
(RegexOptions) 0);

2. how do i append the string "2006" to the authors names found in #1 ?

Use Replace with "$1 2006" as the replacement string.

 

[Guest]

Hi Markus,

thanks, it's work in the Expresso tool but not in the VS2003 IDE find
(Ctrl^F) using regular expression, do you know how to use it in the IDE or
maybe the VS2003 IDE doesn't support this regular expression ?

Thanks.

 

[Markus Stoeger]

let say that my string is :
/// <author> aaa
/// <author> bbb
/// <author> ccc

1. how do i match all the authors except author aaa ?

Regex regex = new Regex(@"(?:///\s<author>\s)([^aaa].+)",
(RegexOptions) 0);

The [^aaa] isn't right.. it means "match any <author> that isn't
followed by *one* 'a'" (instead of three a's). So for example abb will
not match either.

Max

 

[Markus Stoeger]

Hi Markus,

thanks, it's work in the Expresso tool but not in the VS2003 IDE find
(Ctrl^F) using regular expression, do you know how to use it in the IDE or
maybe the VS2003 IDE doesn't support this regular expression ?

I thought you wanted to do this with code (using the Regex class)..

What they have in the CTRL-F dialog doesn't look like the regular
expressions I'm used to.. but this should work:

search for:

{/// \<author\> ~(aaa).*}

replace with:

\1 2006

hth,
Max

 

[Ken Arway]

Regex regex = new Regex(@"(?:///\s<author>\s)([^aaa].+)",
(RegexOptions) 0);

The [^aaa] isn't right.. it means "match any <author> that isn't
followed by *one* 'a'" (instead of three a's). So for example abb will
not match either.

Yep...needed to use the negative look-ahead:

Regex regex = new Regex(@"(?:///\s<author>\s)((?!aaa).+)", (RegexOptions) 0);

 

[Guest]

Thanks to all for your help.

I thought you wanted to do this with code (using the Regex class)..

What they have in the CTRL-F dialog doesn't look like the regular
expressions I'm used to.. but this should work:

search for:

{/// \<author\> ~(aaa).*}

replace with:

\1 2006

hth,
Max