question about the initialization of an array of generic queue

[chrisben]

Here are the codes

Queue<string>[] q = new Queue<string>[2];

Console.WriteLine(q[0].Count + "");

The program will crash since q[0] is null.

So my question is that what is the best way for new to initialize the array
with generic queue as the value?

I can do for statement and then do q = new Queue<string>();

But,is there a better way to do it?

Thanks

Chris

 

[Marc Gravell]

But,is there a better way to do it?

No, not really. Array values initialize to their default values: 0 /
false / null / etc. Assuming you want each item in the array to be a
different queue, you will need to loop and create (new) a different
object for each.

Marc

 

[Ben Voigt [C++ MVP]]

Here are the codes

Queue<string>[] q = new Queue<string>[2];

Console.WriteLine(q[0].Count + "");

The program will crash since q[0] is null.

So my question is that what is the best way for new to initialize the
array with generic queue as the value?

I can do for statement and then do q = new Queue<string>();

But,is there a better way to do it?

Well, you can always write a reusable function for that:

static class ArrayHelper
{
static void FillUsingDefaultConstructor<T> (this T[] array) where T :
new
{
for( int i = 0; i < array.Length; i++ )
array = new T();
}
}

 

[Michael J. Ryan]

Why not use List<Queue<string>> ?

Here are the codes

Queue<string>[] q = new Queue<string>[2];

Console.WriteLine(q[0].Count + "");

The program will crash since q[0] is null.

So my question is that what is the best way for new to initialize the array
with generic queue as the value?

I can do for statement and then do q = new Queue<string>();

But,is there a better way to do it?

Thanks

Chris