J
John Woodgate
I'm new here, so if I put a foot wrong, please be lenient.
Computer: Dell Dimension 8300
Operating System: Windows XP Home
Error Text: #VALUE!
Problem Description: The problem is with Excel 2003. Microsoft's own
example for the DATEVALUE function, DATEVALUE ("8/22/2008") produces the
error message #VALUE! The other examples, with the month in alphabetic
characters, do not produce the error. I've tried other formats, such as
8-22-2008 and 22-8-2008 (since I am using English (UK) dates), with the
same result.
I've tried many ways to try to find out why this happens, without
success.
I have a worksheet with 1600 dates in the form '1-10-1997' ('dd-mm-
yyyy') and I need to convert them to ISO format '1997-10-01' (yyyy-mm-
dd), with leading zeros on numbers less than 10.
I have found elsewhere the 'text-to-columns' procedure to split the
original data into three temporary columns (formatted as text) and
reconstitute as dates in a fourth column (formatted as date 'yyyy-mm-
dd') but I can't find a way of adding the leading zeroes, so that
'1-1-1997' reappears as '1997-1-1' at present.
Computer: Dell Dimension 8300
Operating System: Windows XP Home
Error Text: #VALUE!
Problem Description: The problem is with Excel 2003. Microsoft's own
example for the DATEVALUE function, DATEVALUE ("8/22/2008") produces the
error message #VALUE! The other examples, with the month in alphabetic
characters, do not produce the error. I've tried other formats, such as
8-22-2008 and 22-8-2008 (since I am using English (UK) dates), with the
same result.
I've tried many ways to try to find out why this happens, without
success.
I have a worksheet with 1600 dates in the form '1-10-1997' ('dd-mm-
yyyy') and I need to convert them to ISO format '1997-10-01' (yyyy-mm-
dd), with leading zeros on numbers less than 10.
I have found elsewhere the 'text-to-columns' procedure to split the
original data into three temporary columns (formatted as text) and
reconstitute as dates in a fourth column (formatted as date 'yyyy-mm-
dd') but I can't find a way of adding the leading zeroes, so that
'1-1-1997' reappears as '1997-1-1' at present.