Perform action if value in cell - conditional VB stmt

  • Thread starter Thread starter Studebaker
  • Start date Start date
S

Studebaker

Hello,

First, thank everyone for your help to me previously.

I've run into a need repeatedly that I'm sure a VB code will solve.

I have a spreadsheet that contains columns A to J and rows 1 to 100. The
word "Paid" appears sometimes, not always, in column H of my data. I need a
code to repeatedly look for every occurrance of "Paid" in column H and do the
following til the end:
a) highlight the *row* in my data (not the entire row in Excel beyond my
data) that contains the word "Paid" in yellow (I don't want to use
conditional formatting in this instance if it applies)
b) insert 2 rows underneath the row that contains "Paid" & highlight those
rows gray

Thank you very much for your help.

Studebaker
 
this should help...

Sub test()
Dim c As Range

d = WorksheetFunction.CountIf(Range("H:H"), "Paid")
Range("H:H").Cells.SpecialCells(xlCellTypeConstants).Select

Clear = d * 2 + Selection.Count


For Each c In Selection

If c.Value = "Paid" Then c.EntireRow.Interior.ColorIndex = 36 Else
c.EntireRow.Interior.ColorIndex = 0
If c.Value = "Paid" Then Range(c.Offset(1, 0), Cells(c.Row + 2,
c.Column)).Insert shift:=xlDown

Next c

Range("H:H").Cells.SpecialCells(xlCellTypeBlanks).EntireRow.Interior.ColorIndex
= 15

Range(Cells(Clear + 1, 8), Cells(65536,
8)).EntireRow.Interior.ColorIndex = 0

End Sub
 
Hello,

Thank you for this.
I tried to run it but I got a "Compile error: Syntax error" message. The
debugger highlights & has in red font this part of the code:

If c.Value = "Yes" Then Range(c.Offset(1, 0), Cells(c.Row + 2,
c.Column)).Insert shift:=xlDown (all in red font)

Next c (this is not in red font so I assume this is not the problem)

Range("F:F").Cells.SpecialCells(xlCellTypeBlanks).EntireRow.Interior.ColorIndex (this is not in red font so I assume this is not the problem)
= 15 (the "=15" is in red font)

Range(Cells(Clear + 1, 8), Cells(65536,
8)).EntireRow.Interior.ColorIndex = 0 (all in red font)

Can you help?

Thanks very much.
 

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