outcome of: int i = new System.Int32(); ???

[Jeff]

Hey

I'm wondering what the outcome of this is C# code really is:
int i = new System.Int32();

Which one of these scenarios below describe what the outcome is:
#1: A new reference type instance of i set to zero
#2: An uninitialized i variable
#3: An initialized i variable set to zero

I originally thought #3 is the outcome, but i'm not sure any longer

Any suggestions?

Jeff

 

[=?ISO-8859-1?Q?Arne_Vajh=F8j?=]

I'm wondering what the outcome of this is C# code really is:
int i = new System.Int32();

Which one of these scenarios below describe what the outcome is:
#1: A new reference type instance of i set to zero
#2: An uninitialized i variable
#3: An initialized i variable set to zero

I originally thought #3 is the outcome, but i'm not sure any longer

#3

Int32 is a struct and the same as int.

Arne

 

[Brian Gideon]

Hey

I'm wondering what the outcome of this is C# code really is:
int i = new System.Int32();

Which one of these scenarios below describe what the outcome is:
#1: A new reference type instance of i set to zero
#2: An uninitialized i variable
#3: An initialized i variable set to zero

I originally thought #3 is the outcome, but i'm not sure any longer

Any suggestions?

Jeff

Jeff,

What's causing the uncertainty about #3?

Brian