operator question

[Kimmo Laine]

Hi

is there a way todo this in C#

class MyClass {
protected MyType1[] m_MyTypes1;
protected MyType2[] m_MyTypes2;

public MyClass() { . . . }

public MyType1 this[ int position ] {
get {
return m_MyTypes1[ position ];
}
}
public MyType2 this[ int position ] {
get {
return m_MyTypes2[ position ];
}
}
}

void Foo() {
MyClass m = new MyClass();
MyType1 m1 = m[ 1 ];
MyType2 m2 = m[ 1 ];
}

This won´t compile because there can´t be 2 this-operator overloads that
take the same arguments.

Any ideas how i can do this without using direct (SetMyType/GetMyType)
methods?


thx

Kimmo Laine

 

[Nicholas Paldino [.NET/C# MVP]]

Kimmo,

What you want to do is expose typed collections which will have indexers
that return the appropriate type. You can not produce an overload that
returns a different type (with the same parameter list).

I would recommend using a strongly typed collection, and storing those
in your class, exposing them through different properties which return
collection objects where the indexer will return the appropriate type.

Hope this helps.

 

[James Curran]

Well, in C++, where you can overload operator=, it could be done. But in
C#, you cannot overload the assignment operator, so it can't be done. Which
is all for the best, as Nicholas's suggestion is the better way to go.

--
Truth,
James Curran
[erstwhile VC++ MVP]
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