Open a file from excel-2

[A-Design]

Can anyone please tell me how should I write my codes to open a file like
the example below?what ever I tried ,this doesn't work.

Sub test_1()

FILEOPEN = Shell ("c:\Program Files\EC55\EC55.EXE" &
"\\Server\job-dwg-calc\2004\A3-ENERCALC\04021.ecw", vbMaximizedFocus)

End Sub

 

[KL]

This does work for me:

fileOpen = Shell("C:\WINDOWS\notepad.exe " & "c:\test.txt",
vbMaximizedFocus)

Also, I notice that you forget the space after the *.exe file, you should be
trying to achieve a string like this:

"c:\Program Files\EC55\EC55.EXE
\\Server\job-dwg-calc\2004\A3-ENERCALC\04021.ecw"

which means that you should write this:

FILEOPEN = Shell ("c:\Program Files\EC55\EC55.EXE " &
"\\Server\job-dwg-calc\2004\A3-ENERCALC\04021.ecw", vbMaximizedFocus)

However, I have never tried to use this code with an unmapped server
address, so can't guarantee it'll work after you correct the code.

regards,
KL

 

[A-Design]

KL,

With this new string and also the old one I can call the program that I want
but the file that I specified doesn't open on that program until I go to
menu and try to open it that way, although out side of the excel with just a
simple double click on the file I can have it open by that program.

Thanks,
Afshin.

 

[A-Design]

Kl,
Please disregard my previous post, the new string works perfect, the problem
was the file name.
Thanks
Afshin