MID function fails in SQL

[WildlyHarry]

I have a database that I use to capture records and create tables by date.
The current setup has 31 make table queries that are chosen by VBA code based
on the day of the month. I have decided to streamline my process and pass
sql language into a make table that creates a table with the correct name.
Part of this query relies on the "Mid" function to help parse some data in
certain fields. I created a separate database to do the development of
moving from 31 static queries to 1 query with variable sql passed from a
form. Now my new database gives me an error and states that 'Mid' is not
recognized as a built-in function. But the mid function works in the old
database. Any idea why it fails in one and works in the other? I checked
the "References" and they both have the same libraries selected. Thank you
in advance for you help.

 

[Jeff Boyce]

Are you saying that you use a separate table for each "day-of-the-month"?

If so, both you and Access are having to work overtime to overcome your ...
spreadsheets!

In a well-normalized relational database, it isn't necessary to have one
table per day (or week, or month, or year). In fact, to get the best use of
Access' relationally-oriented features and functions, you DON'T want your
data structured like that.

You can keep coming up with work arounds, or you can spend a bit of time
getting your data into a structure that lets Access really work ... you'll
pay now or pay later <g>.

Good luck!

Regards

Jeff Boyce
Microsoft Access MVP

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[De Jager]

I have a database that I use to capture records and create tables by date.
The current setup has 31 make table queries that are chosen by VBA code
based
on the day of the month. I have decided to streamline my process and pass
sql language into a make table that creates a table with the correct name.
Part of this query relies on the "Mid" function to help parse some data in
certain fields. I created a separate database to do the development of
moving from 31 static queries to 1 query with variable sql passed from a
form. Now my new database gives me an error and states that 'Mid' is not
recognized as a built-in function. But the mid function works in the old
database. Any idea why it fails in one and works in the other? I checked
the "References" and they both have the same libraries selected. Thank
you
in advance for you help.

 

[joelgeraldine]

lilmmùù

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