C
CJaM
Hi,
I'm trying to learn about performance counters and use one at the same
time.
I want to see if a particular user needs additional RAM as he states
he does.
MS has so many different counters its hard to tell what to use (and
compare it to)
for such a simple task.
But according to KB 146005, MS states to log these two counters for
suspected memory bottlenecks.
Logical diskTotal/Total)\Avg. Disk Bytes/Transfer
Memory: Pages/sec
Then it says "If the product of these two counters (equals percentage
of the disk access time used by paging) > 10%
on a sustained basis, the system needs more memory.
Easy enough, you'd think.
According to that, yu run a log of those 2 objects for a time, then
multiply the two together and take an average.
I did this and came up with this number: 63756.72233322 A bit more
than 10%..
Then i just happened to read somewhere with nothing to do with MS, and
they suggested comparing those same counters, but
they also said (re: logical disk counter) "Don't forget to convert
bytes to pages by dividing by 4096"
MS says nothing about this, but I then divided my logical disk counter
by 4096, and then took an average and lo and behold I got a 15.5733443
A bit more like it, you can actually read that as 15 or 16%....
I just want to know if the above bit is right or the previous MS way?
Is there a decent (reliable) website that not only tells you what the
counters do, but gives real world examples of how to actually use
them??
TIA
cj
I'm trying to learn about performance counters and use one at the same
time.
I want to see if a particular user needs additional RAM as he states
he does.
MS has so many different counters its hard to tell what to use (and
compare it to)
for such a simple task.
But according to KB 146005, MS states to log these two counters for
suspected memory bottlenecks.
Logical diskTotal/Total)\Avg. Disk Bytes/Transfer
Memory: Pages/sec
Then it says "If the product of these two counters (equals percentage
of the disk access time used by paging) > 10%
on a sustained basis, the system needs more memory.
Easy enough, you'd think.
According to that, yu run a log of those 2 objects for a time, then
multiply the two together and take an average.
I did this and came up with this number: 63756.72233322 A bit more
than 10%..
Then i just happened to read somewhere with nothing to do with MS, and
they suggested comparing those same counters, but
they also said (re: logical disk counter) "Don't forget to convert
bytes to pages by dividing by 4096"
MS says nothing about this, but I then divided my logical disk counter
by 4096, and then took an average and lo and behold I got a 15.5733443
A bit more like it, you can actually read that as 15 or 16%....
I just want to know if the above bit is right or the previous MS way?
Is there a decent (reliable) website that not only tells you what the
counters do, but gives real world examples of how to actually use
them??
TIA
cj