List<string> TrimStart elements

[sjoshi]

Is List.ConvertAll the only way to apply TrimStart to elements of a
List<string> or is there a better way ?
Currently I'm doing this...

List<string> lst = new List<string>();
lst.AddRange(new string[] {"A test", " that you", " need to see!" });
lst = lst.ConvertAll<string>(delegate(string line) { return
line.TrimStart(null); });

thanks
Sunit

 

[Jon Skeet [C# MVP]]

Is List.ConvertAll the only way to apply TrimStart to elements of a
List<string> or is there a better way ?
Currently I'm doing this...

List<string> lst = new List<string>();
lst.AddRange(new string[] {"A test", " that you", " need to see!" });
lst = lst.ConvertAll<string>(delegate(string line) { return
line.TrimStart(null); });

That's fine, yes. Nicer in C# 3, of course:

lst = lst.ConvertAll(line => line.TrimStart(null));

 

[Peter Duniho]

Is List.ConvertAll the only way to apply TrimStart to elements of a
List<string> or is there a better way ?
Currently I'm doing this...

List<string> lst = new List<string>();
lst.AddRange(new string[] {"A test", " that you", " need to see!" });
lst = lst.ConvertAll<string>(delegate(string line) { return
line.TrimStart(null); });

Since the String class is immutable, I think the List.ConvertAll()
method is a reasonably nice solution. You'll need _some_ sort of code
that replaces each list element with a new item, and that's pretty much
what ConvertAll() is for.

Other than an explicit for() loop indexing each list element, I don't
see any obvious alternative that is similarly compact and easy-to-read.

Is there something specific about List.ConvertAll() that you don't like?

Pete