Inserting rows before page break

R

Robert Christie

Hi everyone
I have a list of student names, M/F, D.O.B., Test results
etc. sorted by their assigned classroom number. Rooms
numbers can vary in sequence and total off i.e.
4,5,6,9,12,16, etc.etc.
The number of students in each class can also vary but a
classroom will always fit on the one page.

I can find the starting row of each room by using a
helper column and inserting a blank row and page break.

What I would like to do is move the starting row of room
5 down to row 38 (start of page 2 landscape format).
Then move room 6 down to row 74 (start of page 3
landscape format) and so on until and including the last
room number, to end up with a classroom on each page with
spare blank rows for teachers use.

The page size ,margins, headers and footers have been set
previously.

Season Greetings to all.
Hope you can help.

TIA

Bob C
 
T

Tom Ogilvy

Seems it would be easer to just apply an autofilter
(Data=>filter=>Autofilter) filter on each room, print, filter on the next
and so forth. (the dropdown arrows for the filter don't print).
 
R

Robert Christie

Thank you for reply Tom.
I'm trying to fully automate the formating from a .CSV
file to a spreadsheet. A second sheet allows the user to
print all classroom sheets or specific classrooms. Using
autofilter will not give me the extra blank rows under
last name, hence the requirement to move rows down.

TIA
Bob C
 
T

Tom Ogilvy

If you have 100 names and you set the print area to A1:J110, then applying
the filter and printing will include 10 rows at the bottom for each class
(barring going beyond the pagebreak).

the other way would be to have one fully formatted class sheet, then use the
autofilter on your data sheet, copy the rows over to the formatted sheet
(only visible rows are copied by default), print (clear that data), and
repeat for each class. (or use the advanced filter).

Working with pagebreaks is slow and unreliable. For instance, horizontal
pagebreaks which don't have data below them, don't even show up in the
pagebreaks collection - so you wouldn't be able to find them with code -
unless you counted down a fixed number of rows (assumes all row heights are
equal).
 
T

Tom Ogilvy

If you want to pursue you first approach, here is some starter code from I
previous post I made:


Here is a method to get an array of horizontal pagebreaks and vertical
pagebreaks. The horizontal pagebreaks are a list of rows that have the
pagebreak and vertical a list of column numbers:

Sub Tester1()
Dim horzpbArray()
Dim verpbArray()
ThisWorkbook.Names.Add Name:="hzPB", _
RefersToR1C1:="=GET.DOCUMENT(64,""Sheet1"")"
ThisWorkbook.Names.Add Name:="vPB", _
RefersToR1C1:="=GET.DOCUMENT(65,""Sheet1"")"
i = 1
While Not IsError(Evaluate("Index(hzPB," & i & ")"))
ReDim Preserve horzpbArray(1 To i)
horzpbArray(i) = Evaluate("Index(hzPB," & i & ")")
i = i + 1
Wend
ReDim Preserve horzpbArray(1 To i - 1)
Debug.Print "Horizontal Pagebreaks (rows):"
For J = LBound(horzpbArray, 1) To UBound(horzpbArray, 1)
Debug.Print J, horzpbArray(J)
Next J

i = 1
While Not IsError(Evaluate("Index(vPB," & i & ")"))
ReDim Preserve verpbArray(1 To i)
verpbArray(i) = Evaluate("Index(vPB," & i & ")")
i = i + 1
Wend
ReDim Preserve verpbArray(1 To i - 1)
Debug.Print "Vertical Pagebreaks (columns):"
For J = LBound(verpbArray, 1) To UBound(verpbArray, 1)
Debug.Print J, verpbArray(J)
Next J
End Sub

This uses an Excel 4 macro to get this information. This is much faster
than the VBA pagebreak which uses the printer driver and can be very slow.

The is a pagebreak property of the range. It can be tested to see if a
pagebreak exists

if rows(6).pagebreak = xlNone then
'No pagebreak
Else
' Has pagebreak
if rows(6).pagebreak = xlPageBreakAutomatic then
'Automatic pagebreak
elseif rows(6).pagebreak = xlPageBreakManual then
' Manual pagebreak
End if
End if


Combining the above gives:

Sub Tester1()
Dim horzpbArray()
Dim verpbArray()
Dim brkType As String
ThisWorkbook.Names.Add Name:="hzPB", _
RefersToR1C1:="=GET.DOCUMENT(64,""Sheet1"")"
ThisWorkbook.Names.Add Name:="vPB", _
RefersToR1C1:="=GET.DOCUMENT(65,""Sheet1"")"
i = 1
While Not IsError(Evaluate("Index(hzPB," & i & ")"))
ReDim Preserve horzpbArray(1 To i)
horzpbArray(i) = Evaluate("Index(hzPB," & i & ")")
i = i + 1
Wend
ReDim Preserve horzpbArray(1 To i - 1)
Debug.Print "Horizontal Pagebreaks (rows):"
For j = LBound(horzpbArray, 1) To UBound(horzpbArray, 1)
If Rows(horzpbArray(j)).PageBreak = xlNone Then
brkType = "None"
Else
' Has pagebreak
If Rows(horzpbArray(j)).PageBreak = xlPageBreakAutomatic Then
brkType = "Automatic"
ElseIf Rows(horzpbArray(j)).PageBreak = xlPageBreakManual Then
brkType = "Manual"
Else
brkType = "Unknown"
End If
End If

Debug.Print j, horzpbArray(j), brkType
Next j

i = 1
While Not IsError(Evaluate("Index(vPB," & i & ")"))
ReDim Preserve verpbArray(1 To i)
verpbArray(i) = Evaluate("Index(vPB," & i & ")")
i = i + 1
Wend
ReDim Preserve verpbArray(1 To i - 1)
Debug.Print "Vertical Pagebreaks (columns):"
For j = LBound(verpbArray, 1) To UBound(verpbArray, 1)
If Columns(verpbArray(j)).PageBreak = xlNone Then
brkType = "None"
Else
' Has pagebreak
If Columns(verpbArray(j)).PageBreak = xlPageBreakAutomatic Then
brkType = "Automatic"
ElseIf Columns(verpbArray(j)).PageBreak = xlPageBreakManual Then
brkType = "Manual"
Else
brkType = "Unknown"
End If
End If

Debug.Print j, verpbArray(j), brkType
Next j
End Sub

Sample Output:
Horizontal Pagebreaks (rows):
1 13 Manual
2 24 Manual
3 39 Manual
4 67 Manual
5 87 Manual
6 114 Automatic
Vertical Pagebreaks (columns):
1 2 Manual
2 6 Automatic

This should get you started.

Regards,
Tom Ogilvy
 
R

Robert Christie

Thankyou again Tom
Your second post made me stop and think out side the
square, and that will be the way I go for now.
Thankyou for the code I'll have a look and a play with it
later on, when time permits, it looks intriguing at first
glance.
And thankyou for your time and effort, very much
appreciated.

Season greetings to you and your family.

Bob C
 

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