increment an integer in a formula with the fill function

  • Thread starter Thread starter vexed
  • Start date Start date
V

vexed

Hi--
there must be a way to do this that I am missing. I want to fill a column
with incremental multiples (2-36) of a constant cell. If I type
$A$1*2
$A$1*3
and then try to fill the series, it doesn't work. Cell A1 represents a
dollar amount, I want to see that amount multiplied by # of months for 36
months in a column. Why can't I get the integer to increment by filling the
series? How should I do this??? Thanks!
 
=$A$1*ROW(A2)

--
HTH

Bob

(there's no email, no snail mail, but somewhere should be gmail in my addy)
 
use =$A$1*ROW()

depending on what the first row is, you may have to subtract 1 or 2 from ROW()

--
Kind regards,

Niek Otten
Microsoft MVP - Excel

| Hi--
| there must be a way to do this that I am missing. I want to fill a column
| with incremental multiples (2-36) of a constant cell. If I type
| $A$1*2
| $A$1*3
| and then try to fill the series, it doesn't work. Cell A1 represents a
| dollar amount, I want to see that amount multiplied by # of months for 36
| months in a column. Why can't I get the integer to increment by filling the
| series? How should I do this??? Thanks!
 
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