IIF Statement #Error

[rml]

I have a query with three fields. ID, Standard, Report

I'm trying to use the following code in the field line:

Report:
IIf([Standard]=1,"abc",IIf([Standard]=2,"stop",IIf([Standard]=3,"nice")))
But the values in Report are #Error?

What am I doing wrong? Thanks.

 

[Jerry Whittle]

You are missing the False part after "nice".

 

[rml]

Can you show me what you mean? Example? Thanks.

You are missing the False part after "nice".
--
Jerry Whittle, Microsoft Access MVP
Light. Strong. Cheap. Pick two. Keith Bontrager - Bicycle Builder.

I have a query with three fields. ID, Standard, Report

I'm trying to use the following code in the field line:

Report:
IIf([Standard]=1,"abc",IIf([Standard]=2,"stop",IIf([Standard]=3,"nice")))
But the values in Report are #Error?

What am I doing wrong? Thanks.

 

[rml]

I'm still getting an #Error for the value? Any more ideas?

I'm putting it on the field line in my query.

Type:
IIf([Standard]=1,"abc",IIf([Standard]=2,"stop",IIf([Standard]=3,"nice","")))

Thanks.

I think what Jerry means is that you need to establish a "If then else"
statement. An IIF statement works in a fashion that essentially says "If this
criteria is met then do this, if the criteria is not met then do that (else)".
Your IIF statement is saying "If this criteria is met then do this" three
times, without establishing the "if the criteria is not met then do that
(else)" portion.

If [Standard] only has applicable values of 1, 2, or 3 then you can have your
else statement do nothing and it should work. That last comma followed by the
two quotes fullfills the else portion.

IIf([Standard]=1,"abc",IIf([Standard]=2,"stop",IIf([Standard]=3,"nice","")))

I have a query with three fields. ID, Standard, Report

I'm trying to use the following code in the field line:

Report:
IIf([Standard]=1,"abc",IIf([Standard]=2,"stop",IIf([Standard]=3,"nice")))
But the values in Report are #Error?

What am I doing wrong? Thanks.

 

[Jerry Whittle]

Is Standard a text or number field? If text, you may need to put double
quotes around the 1, 2, and 3.

There's also a possible problem with "Type". It's a reserved word and
shouldn't be used for table or field names. Try "TheType".

For more on reserved words see:
http://support.microsoft.com/kb/286335/
--
Jerry Whittle, Microsoft Access MVP
Light. Strong. Cheap. Pick two. Keith Bontrager - Bicycle Builder.

I'm still getting an #Error for the value? Any more ideas?

I'm putting it on the field line in my query.

Type:
IIf([Standard]=1,"abc",IIf([Standard]=2,"stop",IIf([Standard]=3,"nice","")))

Thanks.

I think what Jerry means is that you need to establish a "If then else"
statement. An IIF statement works in a fashion that essentially says "If this
criteria is met then do this, if the criteria is not met then do that (else)".
Your IIF statement is saying "If this criteria is met then do this" three
times, without establishing the "if the criteria is not met then do that
(else)" portion.

If [Standard] only has applicable values of 1, 2, or 3 then you can have your
else statement do nothing and it should work. That last comma followed by the
two quotes fullfills the else portion.

IIf([Standard]=1,"abc",IIf([Standard]=2,"stop",IIf([Standard]=3,"nice","")))

I have a query with three fields. ID, Standard, Report

I'm trying to use the following code in the field line:

Report:
IIf([Standard]=1,"abc",IIf([Standard]=2,"stop",IIf([Standard]=3,"nice")))
But the values in Report are #Error?

What am I doing wrong? Thanks.