IF NOT between

M

Miree

I curently have this code which works wonderfully, i need to adapt it to
delete a line if the value in column DW in NOT equal to or between the values
in text boxes 5 and 6 (5 always being less than or equal to 6)

Dim rng As Range
Dim i As Long

Set rng = ActiveSheet.Range(Cells(1, "DW"), Cells(Rows.Count, "DW").End(xlUp))

With rng
For i = .Rows.Count To 1 Step -1
If .Cells(i) = UserForm7.TextBox5 Then
.Cells(i).EntireRow.Delete
End If
Next i
End With

All help very much appreciated

Thanks
 
N

Nigel

If .Cells(i) < UserForm7.TextBox5 Or .Cells(i) > UserForm7.TextBox6 Then
.Cells(i).EntireRow.Delete
End If
 
R

Rick Rothstein

The If..Then statement looks correct to me (given the description of what
you said you wanted to do). Did you actually try the statement or did you
just look at it and decide it was the same as what you tried earlier? Are
you sure you tried the SAME statement as Nigel posted... with the SAME
comparison operators he shows?
 
M

Miree

I was sure this was what I did but tested it anyway and it still did not
work. This is the full code I used maybe the problem is somewhere else

Sub FluidVolumeFilter()

If UserForm7.TextBox6 = "" Then
UserForm7.TextBox6 = UserForm7.TextBox5
End If

If UserForm7.TextBox5 = "" Then
UserForm7.TextBox5 = UserForm7.TextBox6
End If


Dim rng As Range
Dim i As Long

Set rng = ActiveSheet.Range(Cells(1, "DW"), Cells(Rows.Count, "DW").End(xlUp))

'Work backwards from bottom to top when deleting rows

With rng
For i = .Rows.Count To 1 Step -1
If .Cells(i) < UserForm7.TextBox5 Or .Cells(i) > UserForm7.TextBox6
Then
.Cells(i).EntireRow.Delete
End If

Next i
End With
End Sub
 
N

Nigel

Are you testing strings? Because the values in the cells may have unseen
space at the end, this is also true for the form controls.

I generally remove spaces before any string tests, using the TRIM function.

If trim(.Cells(i)) < Trim(UserForm7.TextBox5) Or trim(.Cells(i)) >
Trim(UserForm7.TextBox6)

You might want to assign the test values to variables before the logical
test, especially if you intend to use them in later tests, as the code can
get a bit messy. For example

With UserForm7
sTB5 = Trim(.TextBox5)
sTB6 = Trim(.TextBox6)
End With

For i = .Rows.Count To 1 Step -1
sCell = Trim(.cells(i))

If sCell < sTB5 Or sCell > sTB6 then


etc.



--

Regards,
Nigel
(e-mail address removed)
 
M

Miree

Almost perfect, works most of the time but not if i use a 3 digit and 4 digit
number
 
N

Nigel

You might need to use a type conversion to ensure the test is applied to
numerical values

e.g.

dblVar = cDbl(yourValue)

--

Regards,
Nigel
(e-mail address removed)
 
M

Miree

I tried this, but didnt work can you tell me what i am doing wrong, all of
your help is super appreciated.

If UserForm7.TextBox6 = "" Then
UserForm7.TextBox6 = UserForm7.TextBox5
End If

If UserForm7.TextBox5 = "" Then
UserForm7.TextBox5 = UserForm7.TextBox6
End If

x = CDbl(Trim(UserForm7.TextBox5))
y = CDbl(Trim(UserForm7.TextBox6))


Dim rng As Range
Dim i As Long

Set rng = ActiveSheet.Range(Cells(1, "DW"), Cells(Rows.Count, "DW").End(xlUp))

'Work backwards from bottom to top when deleting rows

With rng
For i = .Rows.Count To 1 Step -1
If Trim(.Cells(i)) < x Or Trim(.Cells(i)) > y Then
.Cells(i).EntireRow.Delete
End If

Next i
End With
 
N

Nigel

I have built your code and form into Excel 2007, and it works fine.

What entries are you making into the UserForm?
What are the range of values in column DW


--

Regards,
Nigel
(e-mail address removed)
 
M

Miree

the values range from 100 to 5000, it works if i use any two 3digit numbers
or any two 4digit numbers but when i use a 3digit and 4digit number (was
trying 700 and 1400)it deletes all of the rows
 
N

Nigel

I have just recreated your values from 100 to 2000, put in 700 and 1400 and
only the values that lie within this range were deleted.

I am not aware of any differences between 2003 and 2007 in this respect, but
you never know. I cannot try this as I do not have this version on my
machine.

Maybe someone else can try for you.

--

Regards,
Nigel
(e-mail address removed)
 
M

Miree

I will have another look at this problem is maybe else where in the code,
thank you so much for all of your help
 

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