G
Guest
Good afternoon,
I need a VBA command that will set the current directory in Access to a
specific folder, so that even if I change the current directory by opening a
file from a different directory, when the sub runs, the directory will be set
to specific folder when I use the show command for the open dialogue box.
This is my code, but for some reason doesn't open the proper directory and
only opens whatever the last directory opened in the application.
Dim OBJ As Object
Set OBJ = GetObject(, "EXCEL.APPLICATION")
Dim SPATh As String
OBJ.Visible = True
SPATh = "C:\SCR DATABASE\CURRENT YEAR Data And Charts\SCR\SCR SUMMARY"
ChDrive SPATh
ChDir SPATh
OBJ.Application.Dialogs(xlDialogOpen).Show
I need a VBA command that will set the current directory in Access to a
specific folder, so that even if I change the current directory by opening a
file from a different directory, when the sub runs, the directory will be set
to specific folder when I use the show command for the open dialogue box.
This is my code, but for some reason doesn't open the proper directory and
only opens whatever the last directory opened in the application.
Dim OBJ As Object
Set OBJ = GetObject(, "EXCEL.APPLICATION")
Dim SPATh As String
OBJ.Visible = True
SPATh = "C:\SCR DATABASE\CURRENT YEAR Data And Charts\SCR\SCR SUMMARY"
ChDrive SPATh
ChDir SPATh
OBJ.Application.Dialogs(xlDialogOpen).Show