G Guest Oct 18, 2005 #1 I need a formula that does this: IF CELL G3 HAS TEXT OF ANY KIND, THEN G34*.15, IF G3 IS BLANK, THEN 0. Help!!!
I need a formula that does this: IF CELL G3 HAS TEXT OF ANY KIND, THEN G34*.15, IF G3 IS BLANK, THEN 0. Help!!!
P Peo Sjoblom Oct 18, 2005 #3 =IF(AND(ISTEXT(G3),G3<>""),G34*0.15,0) if you by "text of any kind" mean a number as well =IF(LEN(G3)>0,G34*0.15,0)
=IF(AND(ISTEXT(G3),G3<>""),G34*0.15,0) if you by "text of any kind" mean a number as well =IF(LEN(G3)>0,G34*0.15,0)
S Sandy Mann Oct 18, 2005 #6 If you mean text in G1 but ignore numbers and errors then try =(ISTEXT(G3))*G34*0.15 If you mean any entry in G1 the try: =(G3<>"")*G34*0.15 -- HTH Sandy (e-mail address removed) Replace@mailinator with @tiscali.co.uk
If you mean text in G1 but ignore numbers and errors then try =(ISTEXT(G3))*G34*0.15 If you mean any entry in G1 the try: =(G3<>"")*G34*0.15 -- HTH Sandy (e-mail address removed) Replace@mailinator with @tiscali.co.uk
S Sandy Mann Oct 18, 2005 #7 Aladin Akyurek said: 1. =(ISTEXT(G3))*(G34*0.15) 2. =IF(ISTEXT(G3),G34*0.15,0) Click to expand... Sandy Mann said: If you mean text in G1 but ignore numbers and errors then try =(ISTEXT(G3))*G34*0.15 If you mean any entry in G1 the try: =(G3<>"")*G34*0.15 Click to expand... mmmm.... Going to have to spend less time reading off line..... <g> Sandy
Aladin Akyurek said: 1. =(ISTEXT(G3))*(G34*0.15) 2. =IF(ISTEXT(G3),G34*0.15,0) Click to expand... Sandy Mann said: If you mean text in G1 but ignore numbers and errors then try =(ISTEXT(G3))*G34*0.15 If you mean any entry in G1 the try: =(G3<>"")*G34*0.15 Click to expand... mmmm.... Going to have to spend less time reading off line..... <g> Sandy