I don´t view the value right after six decimal place in Excel

[Claudio]

From the sixth decimal place of any number in Excel does not present the
accuracy of the system in Cobol.

Would I like to do this in Excel? (have the same accuracy from the sixth home)

If necessary I send the file in Excel showing differences in the accuracy of
calculating the System in Cobol x Microsoft Excel 2003.

Other e-mail: (e-mail address removed)

 

[joeu2004]

I do not know which implementation of COBOL you refer to, and it has
many years (decades!) since I looked at the COBOL language. (I was
never really a COBOL programmer, but I married one :->.)

As I recall, COBOL has a data type that maintains fractional digits in
decimal. So there might be differences between the COBOL
representation and the Excel representation. (Excel maintains numeric
values using the standard IEEE floating-point internal
representation.)

If that is the root cause of the differences that you see, I am not
sure there is any way to guarantee getting the same results in COBOL
and Excel. There are decimal arithmetic add-ons for Excel; do a
Google search. I am not familiar with any of them; I cannot say
whether or not they will match the COBOL results of arithmetic
operations.


------ original posting -----

 

[joeu2004]

PS....

From the sixth decimal place of any number in Excel does not present
the accuracy of the system in Cobol.
Would I like to do this in Excel? (have the same accuracy from the sixth
home)

This might help.....

For every calculation, use the ROUND() function to set the result to
the desired precision. You might want to do that around intermediate
results (subexpressions) as well as final results. This ensures that
the internal binary representation is exactly the same as if you had
entered the result as a constant.

That still might have the same effect as COBOL decimal arithmetic.
But it should reduce the effects of "propagation error". Consider
this example: enter =100*ROUND(2.00666666666667,2)-200 and compare
with 1. They are not identical in Excel 2003. Now compare 1 with
round(100*ROUND(2.00666666666667,2),0)-200.

You might consider setting the option Tools > Options > Calculation >
Precision As Displayed. But first, I believe that affects only the
final result, not intermediated calculations (subexpressions). And
second, it might not have the desired effect when using values with
different precisions.

If you experiment with this option, it would be wise to make a copy of
the workbook first because some changes cannot be undone by simply
unsetting the option and recalculating.

 

[Claudio]

The procedure informed does not work. I wish that I send the Schedules so you
can make the tests?
If so, tell me your e-mail. Thank you.