How to get the network path using OpenFileDialog?

[VhD50]

Hi,
I'm using the OpenFileDialog to let the user pick a file, then I need to get
the file name and file path of the picked file and store it in a database.
My problem comes in when the user picks files from a network folder. Instead
of getting the real file path, i.e. \\servername\sharedfolder, what I get is
the drive letter of the mapped drive. So, instead of having the true path
like '\\servername\sharedfolder\filename.txt', now I get something like
'M:\filename.txt'.
Is there any way I can get the real file path? If possible, please give me
some sample code.
Thanks in advance for your help.

 

[Guest]

VhD50,

A couple of places to start with:

http://www.codeproject.com/csharp/networkshares.asp

http://www.dotnet247.com/247reference/msgs/16/82735.aspx

Kerry Moorman

 

[Sergey Novogilov]

Hi,

Our product, Dialog Workshop .NET contains special customized Open/Save
dialogs
which allow to extend the functionality of standard .NET Open/Save dialogs.
Our dialogs allow to get full remote folder path like this:

ftp://[email protected]/yourfolder

Please visit http://www.componentage.com for details.
Also please Dialog Workshop .NET user's manual, "Working with remote
folders" topic.

With Best Regards,
Sergey