If you wish to display the day of the week as part of your result use
DATENAME (I wanted the day of the week so I used the following. weekday
is a sql key word and 'added_date' is my column name):
datename(weekday, added_date)as day_of_week
DATENAME
Returns a character string representing the specified datepart of the
specified date.
Syntax
DATENAME ( datepart , date )
Arguments
datepart
Datepart Abbreviations
year yy, yyyy
quarter qq, q
month mm, m
dayofyear dy, y
day dd, d
week wk, ww
weekday dw
hour hh
minute mi, n
second ss, s
millisecond ms
The weekday (dw) datepart returns the day of the week (Sunday, Monday,
and so on).
If you specify only the last two digits of the year, values less than
or equal to the last two digits of the value of the two digit year
cutoff configuration option are in the same century as the cutoff year.
Values greater than the last two digits of the value of this option are
in the century that precedes the cutoff year. For example, if two digit
year cutoff is 2049 (default), 49 is interpreted as 2049 and 2050 is
interpreted as 1950. To avoid ambiguity, use four-digit years.
Return Types
nvarchar
Remarks
SQL Server automatically converts between character and datetime values
as necessary, for example, when you compare a character value with a
datetime value.
Examples
This example extracts the month name from the date returned by
GETDATE.
SELECT DATENAME(month, getdate()) AS 'Month Name'
Here is the result set:
Month Name
------------------------------
February
I have searched and searched on the web, but can't seem to find the answer
to this. I can't imagine it would be too hard.
How can I display the day of the week (for example: "Monday", "Tuesday",
"Wednesday") in my Date/Time field?
Thanks !!
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