getting the dimensions/location of a workbook



I have been trying to get the RECT of a workbook but it always comes
back wrong - including the formula bar above the workbook!

Here's how I find the handle of the current workbook window :

private IntPtr findWorkbookHwnd(Excel.Application xl, string caption)
//Get the main Excel window
IntPtr hWndExcel = new IntPtr(xl.Hwnd);

//Find the desktop
IntPtr XLDesk = User32.FindWindowEx(hWndExcel, IntPtr.Zero,
"XLDESK", IntPtr.Zero);

//Find the workbook window
return User32.FindWindowEx(XLDesk, IntPtr.Zero, "EXCEL7", caption);

and here's how I've been getting the Image of the workbook window (from

private Image getImage(IntPtr Hwnd)
// get the hDC of the target window
IntPtr hdcSrc = User32.GetWindowDC(Hwnd);

// get the size
User32.RECT windowRect = new User32.RECT();
User32.GetClientRect(Hwnd, out windowRect);
int top =;
int left = windowRect.left;
int width = windowRect.right - windowRect.left;
int height = windowRect.bottom -;

// create a device context we can copy to
IntPtr hdcDest = GDI32.CreateCompatibleDC(hdcSrc);

// create a bitmap we can copy it to
IntPtr hBitmap = GDI32.CreateCompatibleBitmap(hdcSrc, width,

// select the bitmap object
IntPtr hOld = GDI32.SelectObject(hdcDest, hBitmap);

// bitblt over
GDI32.BitBlt(hdcDest, 0, 0, width, height, hdcSrc, 0, 0,

// restore selection
GDI32.SelectObject(hdcDest, hOld);

// clean up
User32.ReleaseDC(Hwnd, hdcSrc);

// get a .NET image object for it
Image img = Image.FromHbitmap(hBitmap);

// free up the Bitmap object

return img;

but, like I said, I get the wrong screen region back.

It is of the right height and width but it has the wrong x1,y1

Using the windows Accessible Explorer I know that the screen
coordinates of the workbook window are meant to be (321, 580, 920,

The call to
User32.GetClientRect(Hwnd, out windowRect);
returns (0,0,599,317) which is of the right height and width but the
resulting image includes the formula bar.

If I use User32.GetWindowRect(Hwnd, out windowRect) instead, then I get
the coordinates
(555,315,926,338) which I really can't make sense of.

Where on earth am I going wrong?!


I've started from scratch (not that big a deal!) and now I have the
'right' dimensions (i.e. the same as in spy++) so I guess I was just
messing up the output.

I've since realised that the reason it is including the formula bar is
because it is also including the size of the title bar handle (that
appears when a workbook is not maximized).

Not sure how to resize for that...


been messing with SystemInformation.Border3DSize and
SystemInformation.CaptionHeight but I can't work out what these
correspond to...



Does this give better results ?

Private Sub CommandButton1_Click()
Dim hwnd As Long
Dim RetVal As Long
Dim Rectangle As RECT
Dim Msg As String

Select Case ActiveWindow.WindowState
Case xlMinimized
MsgBox "N/A"
Exit Sub
Case xlMaximized
'Get dimensions of "XLDESK" windows
hwnd = FindWindowEx( _
FindWindow("XLMAIN", Application.Caption) _
, 0, "XLDESK", vbNullString)
Case xlNormal
'OK, use WS window
hwnd = FindWindowEx( _
FindWindowEx( _
FindWindow("XLMAIN", Application.Caption) _
, 0, "XLDESK", vbNullString) _
, 0, "EXCEL7", vbNullString)
End Select

If hwnd Then
'RetVal = GetClientRect(hwnd, Rectangle)
RetVal = GetWindowRect(hwnd, Rectangle)
Msg = "My Left is" + Str$(Rectangle.Left) + " Pixels." + Chr$(13) +
"My Top is" + Str$(Rectangle.Top) + " Pixels."
Msg = Msg & vbNewLine & "My Width is" + Str$(Rectangle.Right -
Rectangle.Left) + " Pixels." + Chr$(13) + "My Height is" +
Str$(Rectangle.Bottom - Rectangle.Top) + " Pixels."
MsgBox Msg
MsgBox "Window not found"
End If
End Sub

Out of interest, is this for some kind of screen/window capture ?



Yes, it is for a screen capture.

Unfortunately I've not been able to try out your code suggestion, as
somebody else has taken over the machine I was working on - for the
next few days at least.

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