Get filename from OpenFileDialog

[Luigi]

Hi all,
how can I obtain only the filename with this snippet:

OpenFileDialog dialog = new OpenFileDialog();
string fileName = dialog.FileName;

without the path (C:\etc....)?

Thanks.

 

[Armin Zingler]

Hi all,
how can I obtain only the filename with this snippet:

OpenFileDialog dialog = new OpenFileDialog(); string fileName =
dialog.FileName;

without the path (C:\etc....)?

Thanks.

Have a look at the methods of the System.IO.Path class.


Armin

 

[kimiraikkonen]

Hi all,
how can I obtain only the filename with this snippet:

OpenFileDialog dialog = new OpenFileDialog();
string fileName = dialog.FileName;

without the path (C:\etc....)?

Thanks.

Hi Luigi,
You can get filename with extension using System.IO.Path.GetFilename
method. It removes the rest of the path including folders and returns
only the filename with extension.

As in your sample, you can call:

OpenFileDialog dialog = new OpenFileDialog();
string fileName = System.IO.Path.GetFileName(dialog.FileName);

If you don't want the extension, you can use
"GetFileNameWithoutExtension" method under Path namespace.

HTH,

Onur Güzel