formula too long!

[phil2006]

I have the following formula:
(POISSON(1,0.5*(C1+Sheet1!C52),FALSE))*(POISSON(0,0.5*(C1-Sheet1!C52),FALSE))+(POISSON(2,0.5*(C1+Sheet1!C52),FALSE))*(POISSON(0,0.5*(C1-Sheet1!C52),FALSE))+(POISSON(2,0.5*(C1+Sheet1!C52),FALSE))*(POISSON(0,0.5*(C1-Sheet1!C52),FALSE))+(POISSON(3,0.5*(C1+Sheet1!C52),FALSE))*(POISSON(0,0.5*(C1-Sheet1!C52),FALSE))+(POISSON(4,0.5*(C1+Sheet1!C52),FALSE))*(POISSON(0,0.5*(C1-Sheet1!C52),FALSE))+(POISSON(5,0.5*(C1+Sheet1!C52),FALSE))*(POISSON(6,0.5*(C1-Sheet1!C52),FALSE))+(POISSON(7,0.5*(C1+Sheet1!C52),FALSE))*(POISSON(0,0.5*(C1-Sheet1!C52),FALSE))+(POISSON(2,0.5*(C1+Sheet1!C52),FALSE))*(POISSON(1,0.5*(C1-Sheet1!C52),FALSE))


and need to add more, is there anyway I can reduce the size because i
am being told it is too long!

Thanks

 

[Dann Pedersen]

I have the following formula:

and need to add more, is there anyway I can reduce the size because i
am being told it is too long!

The solution I found was simply to spread the formula over two (og more)
cells, and then simply hiding the "extra" colum.

Hope this helps

/Dann

 

[Bob Phillips]

To start I would create a name (Insert>Name>Define...) of say Half with a
refers to value of

=0.5*(C1+Sheet1!C52)

then another for one formula of say P0 with a refers to value of

=(POISSON(0,Half,FALSE))

and then use

(POISSON(1,0.Half,FALSE))*P0+
(POISSON(2,0.Half,FALSE))*P0+
(POISSON(2,0.Half,FALSE))*P0+
(POISSON(3,0.Half,FALSE))*P0+
(POISSON(4,0.Half,FALSE))*P0+
(POISSON(5,0.Half,FALSE))*(POISSON(6,0.5*(C1-Sheet1!C52),FALSE))+
(POISSON(7,0.Half,FALSE))*P0+
(POISSON(2,0.Half,FALSE))*(POISSON(1,0.5*(C1-Sheet1!C52),FALSE))

or take it further and replace FALSE by 0

(POISSON(1,0.Half,0))*P0+
(POISSON(2,0.Half,0))*P0+
(POISSON(2,0.Half,0))*P0+
(POISSON(3,0.Half,0))*P0+
(POISSON(4,0.Half,0))*P0+
(POISSON(5,0.Half,0))*(POISSON(6,0.5*(C1-Sheet1!C52),0))+
(POISSON(7,0.Half,0))*P0+
(POISSON(2,0.Half,0))*(POISSON(1,0.5*(C1-Sheet1!C52),0))

--
HTH

Bob Phillips

(replace somewhere in email address with gmail if mailing direct)

 

[Guest]

Enter as an array formula with Ctrl+Shift+Enter

=SUM(POISSON({1,2,2,3,4,5,7,2},0.5*B1,FALSE)*POISSON({0,0,0,0,0,6,0,0},0.5*B2,FALSE))


b1= =C1+Sheet1!C52
b2= =C1-Sheet1!C52

with C12=4, C52=2 I returned a result of 0.4991536 using your posing and the
solution above.

HTH

 

[Guest]

....Posing! .... posting!

Enter as an array formula with Ctrl+Shift+Enter

=SUM(POISSON({1,2,2,3,4,5,7,2},0.5*B1,FALSE)*POISSON({0,0,0,0,0,6,0,0},0.5*B2,FALSE))


b1= =C1+Sheet1!C52
b2= =C1-Sheet1!C52

with C12=4, C52=2 I returned a result of 0.4991536 using your posing and the
solution above.

HTH

 

[Guest]

Bob,
The second half of the formula uses C1-Sheet1!C52 so (I believe)
using your solution will give an incorrect result as in your response both
portions are using C1+Sheet1!C52.

To start I would create a name (Insert>Name>Define...) of say Half with a
refers to value of

=0.5*(C1+Sheet1!C52)

then another for one formula of say P0 with a refers to value of

=(POISSON(0,Half,FALSE))

and then use

(POISSON(1,0.Half,FALSE))*P0+
(POISSON(2,0.Half,FALSE))*P0+
(POISSON(2,0.Half,FALSE))*P0+
(POISSON(3,0.Half,FALSE))*P0+
(POISSON(4,0.Half,FALSE))*P0+
(POISSON(5,0.Half,FALSE))*(POISSON(6,0.5*(C1-Sheet1!C52),FALSE))+
(POISSON(7,0.Half,FALSE))*P0+
(POISSON(2,0.Half,FALSE))*(POISSON(1,0.5*(C1-Sheet1!C52),FALSE))

or take it further and replace FALSE by 0

(POISSON(1,0.Half,0))*P0+
(POISSON(2,0.Half,0))*P0+
(POISSON(2,0.Half,0))*P0+
(POISSON(3,0.Half,0))*P0+
(POISSON(4,0.Half,0))*P0+
(POISSON(5,0.Half,0))*(POISSON(6,0.5*(C1-Sheet1!C52),0))+
(POISSON(7,0.Half,0))*P0+
(POISSON(2,0.Half,0))*(POISSON(1,0.5*(C1-Sheet1!C52),0))

--
HTH

Bob Phillips

(replace somewhere in email address with gmail if mailing direct)

 

[Guest]

Building on Bob's proposal:

Enter with Ctrl+Shift+Enter

=SUM(POISSON($I$1:$I$8,PS1,0)*POISSON($J$1:$J$8,PS2,0)

PS1: is named range =0.5*(C1+Sheet1!C52)
PS2: is named range =0.5*(C1-Sheet1!C52)

I1:I8 contain values for PS1
J1:J8 contain values for PS2

HTH

 

[Bob Phillips]

You are right, my P0 should be

=(POISSON(0,0.5*(C1-Sheet1!C52),FALSE))


--
HTH

Bob Phillips

(replace somewhere in email address with gmail if mailing direct)

 

[Tushar Mehta]

This is one of those instances where parsing the formula for patterns raises
some questions.

There is a pattern: Poisson({n},(+),)*(Poisson(0,(-),) which holds for n=
1,2,3,4, and 7.

{n}=2 is repeated. Is that intentional?

Also, there is a break in the pattern at n=5 and n=6 where you have
Poisson(5,(+)) * Poisson (6,(-)). Is that intentional?

And, finally, at the end, you have a Poisson(2,(+))*Poisson(1,(-)). Is that
intentional?

I would address this as follows:

In a separate cell, enter the Poisson(0,(-)) formula.

Put the n values in a column and the corr. Poisson(n,(+)) in the adjacent
column.

Finally, put the Poisson(n,(+))-Poisson(0,(-)) calculations in the next
adjacent column.

Add everything up in a cell below the range that contains the above
analysis.

The result will be dramatically transaparent, easy to read, understand,
debug, and maintain.

--
Regards,

Tushar Mehta
www.tushar-mehta.com
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