Fonts

[Guest]

I have three buttons in the toolbar; Bold, Italic, and Underline. When Bold and Italic are pressed, I want the selection font to be Bold and Italic. I chose this code, but it doesn't work

My Code

if(buttonbold.Pushed == true & buttonitalic.Pushed == true & buttonunderline.Pushed == false
{newfontstyle = FontStyle.Bold & FontStyle.Italic;

In Visual Basic .NET, I would use

newfontstyle = FontStyle.Bold + FontStyle.Itali

But that produces an error in C#. Please help me.

 

[=?ISO-8859-2?Q?Marcin_Grz=EAbski?=]

Hi Bill,

I have three buttons in the toolbar; Bold, Italic, and Underline. When Bold and Italic are pressed, I want the selection font to be Bold and Italic. I chose this code, but it doesn't work.

My Code:

if(buttonbold.Pushed == true & buttonitalic.Pushed == true & buttonunderline.Pushed == false)

This if statement should not work in C# .. because of "&" operator
In C# boolean logic AND operator is represented as "&&".

{newfontstyle = FontStyle.Bold & FontStyle.Italic;}

You made an error here!
"&" (bitwise AND) operator with bit-orthogonal values allways returns
zero.
You should use "|" (bitwise OR) operator to set both bit-orthogonal
values.

{newfontstyle = FontStyle.Bold | FontStyle.Italic;}

In Visual Basic .NET, I would use:

newfontstyle = FontStyle.Bold + FontStyle.Italic

But that produces an error in C#. Please help me.

Regards

Marcin

 

[=?ISO-8859-2?Q?Marcin_Grz=EAbski?=]

Hi Bill,

I have three buttons in the toolbar; Bold, Italic, and Underline. When Bold and Italic are pressed, I want the selection font to be Bold and Italic. I chose this code, but it doesn't work.

My Code:

if(buttonbold.Pushed == true & buttonitalic.Pushed == true & buttonunderline.Pushed == false)

This if statement should not work in C# .. because of "&" operator.
Boolean logic AND operator is represented as "&&" in C#.

{newfontstyle = FontStyle.Bold & FontStyle.Italic;}

You made an error here!
"&" (bitwise AND) operator with bit-orthogonal values allways returns
zero.
You should use "|" (bitwise OR) operator to set both bit-orthogonal
values.

{newfontstyle = FontStyle.Bold | FontStyle.Italic;}

In Visual Basic .NET, I would use:

newfontstyle = FontStyle.Bold + FontStyle.Italic

But that produces an error in C#. Please help me.

On the end, i can show You "better" way to set FontStyle:

newfontstyle =FontStyle.Regular;

if( buttonbold.Pushed ) {
newfontstyle=(newfontstyle | FontStyle.Bold);
}
if( buttonitalic.Pushed ) {
newfontstyle=(newfontstyle | FontStyle.Italic);
}
..
// and next font style
..

Regards

Marcin

 

[Morten Wennevik]

Hi Bill,


This if statement should not work in C# .. because of "&" operator
In C# boolean logic AND operator is represented as "&&".

Actually, both & and && is valid boolean operators. The difference being
if the first statement is false, & causes the next to be checked, while &&
will abort the if statement

int n = 0;
if(++n == 0 & ++n == 0){}

MessageBox.Show(n.ToString()); // shows 2

n = 0;
if(++n == 0 && ++n == 1){}

MessageBox.Show(n.ToString()); // shows 1

-->< snip ><--

Happy coding!
Morten Wennevik [C# MVP]

 

[=?ISO-8859-2?Q?Marcin_Grz=EAbski?=]

Hi Bill,



This if statement should not work in C# .. because of "&" operator
In C# boolean logic AND operator is represented as "&&".

Actually, both & and && is valid boolean operators. The difference
being if the first statement is false, & causes the next to be checked,
while && will abort the if statement

int n = 0;
if(++n == 0 & ++n == 0){}

MessageBox.Show(n.ToString()); // shows 2

n = 0;
if(++n == 0 && ++n == 1){}

MessageBox.Show(n.ToString()); // shows 1

-->< snip ><--

Happy coding!
Morten Wennevik [C# MVP]

ups...

thanx for info!

Cheers!

Marcin